Answer:
4 consecutive odd numbers are 111, 113, 115 and 117.
Step-by-step explanation:
Let the first odd number be x.
So the next odd number will be (x+2)
and the next two consecutive odd numbers are (x+ 4) and (x+6)
According to question,
The sum of all four odd consecutive numbers = 456
⇒ x + (x+ 2) + (x+4) + (x+6) = 456
or, 4x + 12 = 456
⇒ 4x = 456 - 12 = 444
⇒ x = 444/4 = 111
Hence, the first odd number = 111
Second odd number = 111+ 2 = 113
Third odd number is x + 4 = 111 + 4 = 115
And last odd number is x + 6 = 111 + 6 = 117
So, 4 consecutive odd numbers are 111, 113, 115 and 117.
Hey There!
If i am doing this the least common multiple can either be
2 or 4.
thus being
2, 4, 6, 8, 10, 12
Or
4, 8, 12.
Hope This Helps!!!
Answer:
y=(x+2)(x+7)
Step-by-step explanation:
Answer:
No, Isiah is not correct. The GCF of the coefficients is 1, and there are no common variables among all three terms of the polynomial. 5b4 is a factor of -25a2b5 and -35b4, but not a3. Additionally, a2 is a factor of a3 and -25a2b5, but not -35b4.
Step-by-step explanation:
m = 36
<u>Work</u>
<em>45 + 2.50m = 3.75m</em>
<em> -3.75m -3.75m</em>
<em>45 - 1.25m = 0</em>
<em>- 45 - 45</em>
<u><em>-1.25</em></u><em>m = </em><u><em>-45</em></u>
<em>-1.25 -1.25</em>
<em> </em>m = 36
