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den301095 [7]
2 years ago
13

Bounce world offers birthday parties for $140 plus $6 per person. If you can spend no more than $240, how many people can you in

vite to the party?​
Mathematics
1 answer:
ryzh [129]2 years ago
7 0

Answer

The most people you can invite with no more than $240, is 16 people.

Step-by-step explanation:

6x+140=240

6x = 100

x = 16.6666667

Therefore

x = 16.

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Solve for c 6/15=2/c
saul85 [17]
\frac{6}{15} = \frac{2}{c}   Multiply both sides by 15
6 = \frac{30}{c}   Multiply both sides by c
6c = 30   Divide both sides by 6
c = 5   
7 0
2 years ago
Tickets to a movie cost $7.25 for adults and $5.50 for students a group of friends purchased 8 tickets for $52.75 how many adult
irina1246 [14]

Answer:

The number of adults tickets and student tickets purchased is 5 and 3.

Given that,

Tickets to a movie cost $7.25 for adults and $5.50 for students.

A group of friends purchased 8 tickets for $52.75.

Here we assume the no of adult tickets and no of student tickets be x and y.

Based on the above information, the calculation is as follows:

7.25x + 5.50y = 52.75 .............(i)

x + y = 8

x = 8 - y..................(2)

Now put the x value in the equation (1)

So,  

7.25(8-y) + 5.50y = 52.75

7.25 × 8 - 7.25y + 5.50y = 52.75

58 - 1.75y = 52.75

5.25 = 1.75y

y = 3

So,  

x = 8 - 3

= 5

Therefore we can conclude that the number of adults tickets and student tickets purchased is 5 and 3.

-Hope this helps<3

4 0
2 years ago
Find three ratios that are equivalent to 2 4. A. 8 16 B. 10 24 C. 4 8 D. 3 5 E. 6 12 F. 12 6
xenn [34]

Answer:

A, C, and E good luck

Step-by-step explanation:

3 0
2 years ago
A chord is 48 cm long and is 7 cm from the center of the circle. What is the length of the radius (r) of the circle?
ra1l [238]

Answer:

95

Step-by-step explanation:

4 0
2 years ago
Answer quickly please
KIM [24]

The correct answer is C.


You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.


f(x) = x^4 + x^3 - 2x^2


Since each term has at least x^2, we can factor it out.


f(x) = x^2(x^2 + x - 2)


Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.


f(x) = x^2(x + 2)(x - 1)


Now we can also separate the x^2 into 2 x's.


f(x) = (x)(x)(x + 2)(x - 1)


To find the zeros, we need to set them all equal to 0


x = 0


x = 0


x + 2 = 0

x = -2


x - 1 = 0

x = 1


Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.

4 0
3 years ago
Read 2 more answers
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