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dsp73
3 years ago
14

Good Morning can I get some help please?​

Mathematics
2 answers:
lutik1710 [3]3 years ago
5 0
It might be a. sorry if im wrong
Vladimir [108]3 years ago
4 0

Answer:

it is A!! hope this helped mark brainly

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Can yall help me with this plz i cant fail this class
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Answer:

2 or 6

Step-by-step explanation:

Please mark me brainleist

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3 years ago
Which equation has no solution?
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5 + 2(3 + 2x) = x + 3(x + 1) has no solution

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4 years ago
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What percent of 43.75 is 70
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62.5%
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Then I moved the decimal over two places to the right to get 62.5. 
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if the surface area ratio of Sphere A to Sphere B is 9/100 and the surface area of A is 27 units squared, what is the surface ar
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Step-by-step explanation:

6 0
4 years ago
Solve cos x - square 1-3 cos^2 x = 0 given that 0° < x < 360°
Furkat [3]

Rearrange the equation as

cos(x) - √(1 - 3 cos²x) = 0

cos(x) = √(1 - 3 cos²x)

Note that both sides have to be positive, since the square root function is non-negative. If we end up with any solutions that make cos(x) < 0, we must throw them out.

Take the square of both sides.

(cos(x))² = (√(1 - 3 cos²(x))²

cos²(x) = 1 - 3 cos²(x)

4 cos²(x) = 1

cos²(x) = 1/4

cos(x) = ± √(1/4)

cos(x) = ± 1/2

We throw out the negative case and we're left with

cos(x) = 1/2

This has general solution

x = arccos(1/2) + 360° n   or   x = -arccos(1/2) + 360° n

(where n is any integer)

x = 60° + 360° n   or   x = -60° + 360° n

Now just pick out the solutions that fall in the interval 0° ≤ x < 360°.

• From the first solution set, we have x = 60° when n = 0.

• From the second set, we have x = 300° when n = 1.

So the answer is D.

4 0
3 years ago
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