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2 years ago

In the attachment there is a density column where there is colour

Physics

2 answers:

Ratling [72]2 years ago

7 0

The star is pink. Pink is the MOST dense on the list.

The red thing below the star is the foot of the tube that all the liquids and the star are in.

Anettt [7]2 years ago

4 0

Answer:

For your kind information, read the question thoroughly!

The bottom is the container part and not the liquid.

I hope it will be useful.

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There are several ways to model a compound. One type of model is shown. 4 C's are connected in a line by 3 black lines. The C on

stealth61 [152]

Answer:

The chemical formula for the molecule is $C_4H_9O_2$

Explanation :

Molecular formula : It is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Structural formula : It is a formula in which the lines are used between the bonded atoms and the atoms are also shown in the structural formula.

In the structural formula, the lines are used between the atoms.

As per given information of compound we conclude that, there are 4 carbon atoms, 9 hydrogen atoms and 2 oxygen atoms.

Thus, the chemical formula for the given molecule will be, $C_4H_9O_2$

7 0

2 years ago

A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When

natita [175]

Answer:

a) $\mu_{k} = 0.704$ , b) $R = 0.312\,m$

Explanation:

a) The minimum coeffcient of friction is computed by the following expression derived from the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \mu_{k}\cdot m\cdot g \cdot \Delta s$

$\mu_{k} = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \Delta s}$

$\mu_{k} = \frac{\left(8050\,\frac{N}{m} \right)\cdot (0.06\,m)^{2}}{2\cdot (0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (7\,m)}$

$\mu_{k} = 0.704$

b) The speed of the block is determined by using the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}$

$v = x\cdot \sqrt{\frac{k}{m} }$

$v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }$

$v \approx 9.829\,\frac{m}{s}$

The radius of the circular loop is:

$\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}$

$\frac{\left(9.829\,\frac{m}{s}\right)^{2}}{R} = 309.807\,\frac{m}{s^{2}}$

$R = 0.312\,m$

5 0

3 years ago

Find the voltage

son4ous [18]

Answer:

Explanation:

solve the parallel resistances

30||40 and 50||30

17.14285714 and 18.75

total Resistance = 35.89285714

V = IR

9V = I *35.89285714

9V / 35.89285714 = I

0.250746 = I

Now use the resistance across AB

V = 17.14285714 * 0.250746

V = 4.29850

this is the Voltage drop across AB :P

5 0

2 years ago

How would you classify hydrogen

serg [7]

It can be classified with either the alkali metals or halogens; i believe

6 0

3 years ago

Read 2 more answers

A loaded gun is dropped on a frozen lake. The gun fires, with the bullet going horizontally in one direction and the gun sliding

omeli [17]

Answer:

4.96m/s

Explanation:

Using mv = m'v'

m = 0.04kg

v = 285 m/s

m' = 2.3kg

v'= ?

0.04×285 = 2.3v'

V' = 11.4/2.3

= 4.96m/s

5 0

2 years ago