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3 years ago

In the attachment there is a density column where there is colour

Physics

2 answers:

Ratling [72]3 years ago

7 0

The star is pink. Pink is the MOST dense on the list.

The red thing below the star is the foot of the tube that all the liquids and the star are in.

Anettt [7]3 years ago

4 0

Answer:

For your kind information, read the question thoroughly!

The bottom is the container part and not the liquid.

I hope it will be useful.

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A car is moving with speed 60 m/s and acceleration 4 m/s2 at a given instant. (a) using a second-degree taylor polynomial, estim

pantera1 [17]

Answer:

Explanation:

Using second degree taylor polynomials

let $S(t)$ be position function and set $S(0)=0$

where S(0) is the initial position

Then $v(t) = S^i(t)$ and $a(t)=S^{ii}(t)$

we have $v(0) = 60m/s$ , $a(0) = 4m/s^2$

so $T_{2}(t) =S(0)+v(0)t+\frac{a(0)}{2} t^2\\\\\\=0+60t+\frac{4}{2} t^2\\\\T_{2}(t)=60t+2t^2\\\\S(1)=T_{2}(1)=60+2=62m$

b.) yes

6 0

3 years ago

Novosadov [1.4K]

Explanation:

The are the same but difference

8 0

3 years ago

Simple Harmonic Motion

Delvig [45]

- The net force is greatest at the position of maximum displacement

- The net force is zero when at the equilibrium position

Explanation:

The motion of a spring is a Simple Harmonic Motion, in which the displacement of the end of the spring is given by a periodic function of the form

$x=Asin (\omega t)$

where A is the amplitude (the maximum displacement), and $\omega$ the angular frequency of the motion.

We can analyze the net force acting on the spring by looking at Hooke's law:

$F=kx$

where

F is the net force

k is the spring constant

x is the displacement

From the equation, we notice immediately that:

The net force is the greatest when the displacement x is the greates, so at the position in which the spring has maximum compression or stretching
The net force is zero when the displacement x is zero, so when the spring crosses the equilibrium position

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

7 0

3 years ago

If the solar system shrank so that the sun were located just one centimeter from Earth, about how far away could you find the ne

DedPeter [7]

E S *

The "E" represents Earth, "S" represent Sun, and the "*" represents the nearest star(which is Proxima Centauri).

The main thing to worry about here is units, so ill label everything out.
D'e,s'(Distance between earth and sun) = .00001581 light years
D'e,*'(Distance between earth and Proxima) = 4.243 light years

Now this is where it gets fun, we need to put all the light years into centimeters.(theres alot)
In one light year, there are 9.461 * 10^17 centimeters.(the * in this case means multiplication) or 946,100,000,000,000,000 centimeters.

To convert we multiply the light years we found by the big number.
D'e,s'(Distance between earth and sun) = 1.496 * 10^13 centimeters
D'e,*'(Distance between earth and Proxima) = 4.014 * 10^18 centimeters

Now we scale things down, we treat 1.496 * 10^13 centimeters as a SINGLE centimeter, because that's the distance between the earth and the sun. So all we have to do is divide (4.014 * 10^18 ) by (1.496 * 10^13 ).
Why? because that how proportions work.

As a result, you get a mere 268335.7 centimeters.

To put that into perspective, that's only about 1.7 miles

A lot of my numbers came from google, so they are estimations and are not perfect, but its hard to be on really large scales.

8 0

3 years ago

A ring with an 18mm diameter falls off a scientist's finger into the solenoid in the lab. The solenoid is 25 cm long, 5.0 cm in

Troyanec [42]

Answer:

The value is $\epsilon = 3.84 *10^{-5} \ V$