Answer:
Acceleration of Sea Lion is 4.41 g
This is 49% of maximum jet acceleration given as a = 9g
Explanation:
As we know that the radius of the circular loop is given as
R = 0.37 m
The speed of the fish is given as
Now the centripetal acceleration of the sea lion is given as
as we know that
so we have
Now Percentage of this acceleration wrt maximum jet acceleration is given as
%
Hello,
To solve we need to know the formula for speed
The formula is D/T=S (Distance of time=speed)
Now all we have to do is plug in the numbers.
20/40= 1/2 or 0.5
SO the speed is 0.5 m/s
Have a great day!
Hi there!
We can begin by solving for the linear acceleration as we are given sufficient values to do so.
We can use the following equation:
vf = vi + at
Plug in given values:
4 = 9.7 + 4.4a
Solve for a:
a = -1.295 m/s²
We can use the following equation to convert from linear to angular acceleration:
a = αr
a/r = α
Thus:
-1.295/0.61 = -2.124 rad/sec² ⇒ 2.124 rad/sec² since counterclockwise is positive.
Now, we can find the angular displacement using the following:
θ = ωit + 1/2αt²
We must convert the initial velocity of the tire (9.7 m/s) to angular velocity:
v = ωr
v/r = ω
9.7/0.61 = 15.9 rad/sec
Plug into the equation:
θ = 15.9(4.4) + 1/2(2.124)(4.4²) = 20.56 rad
Tension in the rope due to applied force will be given as
angle of applied force with horizontal is 37 degree
displacement along the floor = 6.1 m
so here we can use the formula of work done
now we can plug in all values above
So here work done to pull is given by 691.8 J
