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sineoko [7]
3 years ago
5

A kicker kicks a ball off the ground at 29.5 mi/hr and at 42.5 degrees.

Physics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

20.3m

Explanation:

the formula used was

s=(u^2sin^2∆)÷2g

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The cars on an amusement-park ride travel at a constant velocity of 4.0 m/s on a circular track
lys-0071 [83]
V^2=u^2+2as
V=0
a =-u^2/2s
a=[4]^2/2[4]
a=-2m/s^2
7 0
3 years ago
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Elza [17]

Answer:

maybe its heat sorry if it's wrong

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4 0
3 years ago
1. How would you expect an instantaneous acceleration vs. time graph to look for a cart moving with a constant
r-ruslan [8.4K]

Answer:

a=0   v = v₀ + a t

a=0    line is horizontal

Explanation:

1, In a graph of acceleration vs. time, we have lines, when the line is horizontal it is zero, when the line has a positive slope the increasing accelerations and when the slope is negative the decreasing acceleration

2, speed and relationship of a car is given by

        v = v₀ + a t

where vo is the initial velocity, a is the acceleration and tel time

in this case I will calcograph velocity vs. time the constant acceleration is a straight line.

In general from the graph we can find the initial velocity with the cut at that x and the acceleration of the car with the slope

6 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!! SIGNIFICANT DIGITS!!!!!! THE ANSWER IS NOT −16.422​
Aleks04 [339]

Explanation:

What exactly are u looking for?

7 0
3 years ago
Read 2 more answers
A car is traveling at the bottom of a 9.00-meter-radius circular hill with a constant speed v. The moment the car is at the bott
Rina8888 [55]

Answer:

Explanation:

reading of scale = reaction force of surface R

centripetal force = R - mg = m v² / R , m is mass , v is velocity and R is radius of the circular path .

R = mg + m v² / R

given ,

m v² / R = .80 mg

v² = .80 x g x R

= .8 x 9.8 x 9 = 70.56

v = 8.4 m /s

3 0
3 years ago
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