Different stages of the cycle gives off different wavelengths of light because more types elements are being made as you go farther down the cycle. So looking at the wavelengths that the light gives off can determine what stage a star is currently in
The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.
<h3>Newton's third law of motion</h3>
Newton's third law of motion states action and reaction are equal and opposite. That is the force applied to an object is equal in magnitude to force experienced by the object but in opposite direction.
From the given question, when the bag exert a certain on the athlete, the athlete also exerts similar force to the bag but in opposite direction.
Thus, the complete sentence is as follows;
The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.
Learn more about Newton's third law of motion here: brainly.com/question/25998091
#SPJ1
Answer:
a) Linear equation
Explanation:
Definition of acceleration
if a=constant and we integrate the last equation
So the relation between the time and the velocity is linear. If we plot the velocity in function of time, the plot is a line, and the acceleration is the slope of this line.
Answer:
x = 54.15 meters between the balloons horizontally.
Explanation:
Hence, vertical distance between balloons is 12.8 meters.
y= 61-48.2 = 12.2 m
A right-angle triangle is formed with,
angle θ = 13.3 degrees
opposite (y) = 12.8
adjacent (x) = ?
Now by putting the values in the above equation.
x = 54.15 meters between the balloons horizontally.
Answer:
3.84 m/s
Explanation:
Using Bernoulli's equation below:
P1 + (1/2ρv1²) + h1ρg = P2 + (1/2ρv2²) + h2ρg
where P1 = P2 atmospheric pressure
(1/2ρv1²) + h1ρg = (1/2ρv2²) + h2pg
collect the like terms
h1ρg - h2ρg = (1/2ρv2²) - (1/2ρv1²)
factorize the expression by removing the like terms on both sides
gρ(h1 - h2) = 1/2ρ( v2² - v1²)
divide both side by rho (density in kg/m³, ρ )
g(h1 - h2) = 1/2 (v2² - v1²)
assuming the surface of the tank is large and the speed of water then at the tank surface v1 = 0
2g(h1 - h2) = v2²
take the square root of both side and h1 - h2 is the difference between the surface of the tank and the opening where water is coming out in meters
√2g(h1 - h2) = √ v2²
v2 = √2g(h1-h2) = √ 2 × 9.81×0.75 = 3.84 m/s
