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Licemer1 [7]
3 years ago
11

How much heat is required to raise the temperature of 2.0 kg of concrete from 10C to 30C? (The specific heat of concrete is 880

j/kg-C.)
A. 22 J
B. 88 J
C. 8800 J
D. 35200 J
Physics
1 answer:
Phantasy [73]3 years ago
8 0

Answer:B

Explanation:

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PART ONE
Lina20 [59]

Explanation:

Make a table, listing the x and y coordinates of each square's center of gravity and its mass.  Multiply the coordinates by the mass, add the results for each x and y, then divide by the total mass.

\left\begin{array}{ccccc}x&y&m&xm&ym\\\frac{a}{2} &\frac{a}{2} &10&5a&5a\\\frac{3a}{2}&\frac{a}{2}&70&105a&35a\\\frac{a}{2}&\frac{3a}{2}&80&40a&120a\\\frac{3a}{2}&\frac{3a}{2}&50&75a&75a\\&\sum&210&225a&235a\\&&Avg&\frac{15a}{14}&\frac{47a}{42}\end{array}\right

The x-coordinate of the center of gravity is 15/14 a.

The y-coordinate of the center of gravity is 47/42 a.

4 0
3 years ago
Infrared light of wavelength 2.5 µm illuminates a 0.20-mm-diameter hole. What is the angle of the first dark fringe in radians?
stepan [7]

Answer:

Θ=0.01525 rad

or

Θ=0.87°

Explanation:

Given data

wavelength λ=2.5 µm =2.5×10⁻⁶m

Diameter d=0.20 mm =0.20×10⁻³m

To find

Angle Θ in radians and degree

Solution

Circular apertures have first dark fringe at

Θ=(1.22λ)/d

Substitute the given values

So

Θ=[1.22(2.5×10⁻⁶m)]/0.20×10⁻³m

Θ=0.01525 rad

or

Θ=0.87°

6 0
3 years ago
At what point will the electric field of a charged object be strongest?
maks197457 [2]
The electric field of a charged object will be strongest when all the field lines are close to one another.

beacsue, the strength of electric field depends on the number of lines of electric field. More lines at a place, higher the electric field strength. Thus, any charge in that area will face more electric field.
6 0
3 years ago
Read 2 more answers
Black and splinter cleavage barely scratches glass​
Oksanka [162]

Answer:

oh I know that sounds good to me

4 0
3 years ago
What is the volume V of a sample of 2.30 mol of copper? The atomic mass of copper (Cu) is 63.5 g/mol, and the density of copper
djyliett [7]

Answer:

1.636 x 10^-5 m^3

Explanation:

As we know that

1 mol of copper = 63.5 g of copper

2.3 mol of copper = 63.5 x 2.3 = 146.05 g of copper = 0.146 kg of copper

Density of copper = 8.92 x 10^3 kg/m^3

The relation between mass and volume is given by

mass = volume x density

Volume = \frac{mass}{density}

Volume = \frac{0.146}{8.92\times10^3}=1.636\times10^{-5}m^3

Thus, the volume of copper is 1.636 x 10^-5 m^3.

5 0
3 years ago
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