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Whitepunk [10]
3 years ago
13

If you can buy one pineapple for $4, then how many can you buy with $12?

Mathematics
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

you can buy 3 pineapples

Step-by-step explanation:

$4(3)= $12 total

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Jolene works for a company that does not offer retirement matching. For the last 16 years, Jolene has been depositing $150 into
ki77a [65]

Answer:

$2,543.84 is your answer.

Step-by-step explanation:

What you do first is you have to figure out the 5.99% interest rate.

150 x 5.99 = 8.99

150 + 8.99 = $158.99

Now multiply that by 16

158.99 x 16 = $2,543.84 is your answer.

4 0
3 years ago
What is 85% of 146.54??
lana66690 [7]
Your answer would be 124.559
7 0
3 years ago
ABCD is a rectangle. The perimeter is 140 ft. AB = 40ft Find the length of AC
DiKsa [7]

perimeter =2 (l+b)

140=2 (l+40)

140=2l+80

120/2=l

l=60

4 0
3 years ago
Calculate the amount of heat (in kJ) released when 3.5 mol CH4 react. 4() + 22() → 2() + 22() + 890
In-s [12.5K]

The amount of heat (in KJ) released when 3.5 moles of CH₄ react is 3115 KJ

<h3>Balanced equation</h3>

CH₄ + 2O₂ -> CO₂ + 2H₂O ΔH = 890 KJ

From the balanced equation above,

1 mole of CH₄ reacted to release 890 KJ of heat energy.

<h3>How to determine the heat energy released by 3.5 moles of CH₄</h3>

From the balanced equation above,

1 mole of CH₄ reacted to release 890 KJ of heat energy

Therefore,

3.5 moles of CH₄ will react ro release = 3.5 × 890 = 3115 KJ of heat energy

Thus, 3115 KJ of heat energy were released from the reaction

Learn more about enthalpy change:

brainly.com/question/11967318

#SPJ1

5 0
1 year ago
Consider the polynomials p1(t) = 1 + t , p2(t) = 1 -t , and p3(t) = 2 (for all t). By inspection, write a linear dependence rela
emmasim [6.3K]

Answer:

\{p_1,p_2\}$ is a basis of Span\{p_1,p_2,p_3\}

Step-by-step explanation:

Given the polynomials:

p_1(t) = 1 + t\\ p_2(t) = 1 -t\\p_3(t) = 2\\

On Inspection

(1+t)+(1-t)=1+1+t-t=2\\$Therefore:\\p_1(t)+p_2(t)=p_3(t)

By the Spanning Theorem  

If one vector in S is a linear combination of the others, we can delete it and get a subset (one vector smaller) S' \subseteq S that has the same span.

Therefore, since p_3(t)=p_1(t)+p_2(t)

Span\{p_1,p_2,p_3\}=Span\{p_1,p_2\}

p_1$ and p_2 are linearly independent because p_1 cannot be written in terms of p_2.

Therefore, \{p_1,p_2\}$ is a basis of Span\{p_1,p_2,p_3\}$ as required.

5 0
3 years ago
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