Answer:
2NH4Cl(aq) + Na2CO3(aq) → 2NaCl(aq) + (NH₄)₂CO₃ (s)
2NH4+(aq) + 2Cl-(aq) + 2Na+(aq) + CO3^2-(aq) → 2Na+(aq) + 2Cl-(aq) + (NH₄)₂CO₃ (s)
2NH4+(aq) + CO3^2-(aq) → (NH₄)₂CO₃ (s)
Explanation:
Step 1: Data given
The reactant are NH4Cl and Na2CO3
Step 2: The unbalanced equation
NH4Cl(aq) + Na2CO3(aq) → NaCl(aq) + (NH₄)₂CO₃ (s)
Step 3: Balancing the equation
NH4Cl(aq) + Na2CO3(aq) → NaCl(aq) + (NH₄)₂CO₃ (s)
On the left side we have 2x Na (in Na2CO3) on the right side we have 1x Na. To balance the amount of Na on both sides we have to multiply Nacl by 2
NH4Cl(aq) + Na2CO3(aq) → 2NaCl(aq)+ (NH₄)₂CO₃ (s)
On the right side we have 2x N (in (NH4)2CO3), on the left side we have 1x N (in NH4Cl). To balance the amount of N on both side, we have to multiply NH4Cl by 2.
2NH4Cl(aq) + Na2CO3(aq) → 2NaCl(aq) + (NH₄)₂CO₃ (s)
The total ionic equation
The complete ionic equation is used to describe the chemical reaction while also clearly indicating which of the reactants and/or products exist primarily as ions in aqueous solution.
2NH4+(aq) + 2Cl-(aq) + 2Na+(aq) + CO3^2-(aq) → 2Na+(aq) + 2Cl-(aq) + (NH₄)₂CO₃ (s)
The net ionic equation
In a net ionic equation, all spectator ions are completely removed.
2NH4+(aq) + CO3^2-(aq) → (NH₄)₂CO₃ (s)
