Answer:
The mass percentage of the solution is 10.46%.
The molality of the solution is 2.5403 mol/kg.
Explanation:
A bottle of wine contains 12.9% ethanol by volume.
This means that in 100 mL of solution 12.9 L of alcohol is present.
Volume of alcohol = v = 12.9 L
Mass of the ethanol = m
Density of the ethanol ,d= 
Mass of water = M
Volume of water ,V= 100 mL - 12.9 mL = 87.1 mL
Density of water = D=1.00 g/mL
Mass percent
Molality :
M = 87.1 g = 0.0871 kg (1 kg =1000 g)
Strong acids provide more H+ in the aqueous solution than the weak acids. This excess amount of H+ conducts more electricity in the solution.
Explanation:
The strong acid provides more H+ ion whereas the weak acids produce less H+ in the aqueous solution resulting in less amount of electricity conduction in the solution.
Weak acid- lesser amount of H+ produced
Strong acid- greater amount of H+ ( proton) produced.
1 mole ----------- 6.02x10²³ molecules
? moles --------- 1.9x10²⁵ molecules
moles = 1.9 x 10²⁵ * 1 / 6.02x10²³
= 1.9 x 10²⁵ / 6.02x10²³
= 31.561 moles
hope this helps!
Answer:
12 L of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
CS₂ + 3O₂ —> CO₂ + 2SO₂
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Finally, we shall determine the volume of O₂ required to produce 4 L of CO₂. This can be obtained as follow:
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Therefore, xL of O₂ will react to produce 4 L of CO₂ i.e
xL of O₂ = 3 × 4
xL of O₂ = 12 L
Thus, 12 L of O₂ is needed for the reaction.
