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3 years ago

According to the law of conservation of matter, how must a chemical equation be written

2 answers:

8 0

I think you are suposse to use coefficients of products and reactents to balance the number of atoms of an element on both sides of a chemical equation

i hope this helps

alexira [117]3 years ago

5 0

Answer:

An equal number of atoms must be on both sides of the equation

Explanation:

The quantity of matter that exist after a chemical reaction must equal the amount that existed before it.This means that an equal number of atoms must appear on each side of the chemical equation

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An ideal gas is stored in a container at constant volume. If the temperature (T) were increased to 3T, what would be the change

Olin [163]

According to Gayle Lusac's law, pressure is proportional to absolute temperature of a gas. Thus:
P/T = constant

So if the temperature becomes 3T, the pressure would increase to 3P

6 0

3 years ago

Read 2 more answers

Determine the empirical formulas for compounds with the following percent compositions:

White raven [17]

Answer: a) $CS_2$

b) $CH_2O$

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles$

Moles of S= $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.32}{1.32}=1$

For S = $\frac{2.63}{1.32}=2$

The ratio of C : S = 1:2

Hence the empirical formula is $CS_2$

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.7}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is $CH_2O$

5 0

3 years ago

1. Carbon12 is C. How many atoms of carbon 12 are there in one mole of<br> carbon 12?

Dvinal [7]

Answer:

the answer is 12.01 mole

7 0

3 years ago

Which is a property of potassium (K)?

kumpel [21]

It is highly reactive and when it is kept in open it does react with the oxygen present in the surroundings and burns therefore it is kept immersed in kerosene and please thank me and if you need more comment

5 0

3 years ago

ILL GIVE YOU BRAINLIEST!!!!Which of the following is an example of a description of climate? *

Murrr4er [49]

Answer:

The relative humidity in Raleigh, NC

You can search it up online. Search up what is climate change and it will give you "the weather conditions prevailing in an area in general or over a long period." (On bing)

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

6 0

3 years ago