Trig question Please help

Two bottles are selected at random, without replacement from a drawer containing 2 bottles of coke, 3 bottles of fanta and 4 bot

AVprozaik [17]

To find : outcomes for choosing 2 bottles (without replacement) from 3 various soft drink bottles in different numbers - coke , fanta , sprite

There can be total 2 x 3 , ie = 6 outcomes in this case.

Like two alphabets from A,B,C can be chosen without replacement in following 6 cases - A B & B A , A C & C A , B C & C B

Similarly for Coke , Fanta , Sprite case ; total outcomes are :-

Coke, Fanta
Fanta, Coke
Coke, Sprite
Sprite , Coke
Fanta , Sprite
Sprite , Fanta

For more information, refer brainly.com/question/23489473?referrer=searchResults

5 0

3 years ago

19 is greater than the sum the number n and 3

masha68 [24]

Your answer should be 19>n+3

5 0

2 years ago

An astronaut who weighs 85 kilograms on earth weighs 14.2 kilograms on the moon. How much would a person weigh on the moon if th

STatiana [176]

Answer:

Weight on the moon=x=15.87 kilograms

Step-by-step explanation:

This can be expressed as;

Weight on earth=Constant×Weight on moon

where;

Weight on moon=14.2 kilograms

Constant=k

Weight on Earth=85 kilograms

Replacing in the expression above;

85=14.2×k

k=(85/14.2)=5.986

If the person weighs 95 kilograms on Earth;

Weight on the earth=Constant×Weight on moon

where;

Weight on the moon=x

Constant=5.986

Weight on the earth=95 kilograms

Replacing;

95=5.986×x

x=95/5.986=15.87

Weight on the moon=x=15.87 kilograms

4 0

3 years ago

So in my math homework lesson today we are learning “Solve One-Step Problems”. I don’t completely understand how to do it. I was

Sedaia [141]

Answer:

Step-by-step explanation:

So, in this problem, we're given the size of the of the file. We are also given the rate of change of the amount-downloaded function.

Notice how the transfer rate is in units of time (25.2 MB/s means 25.2 MB per second).

If we want to calculate how long it'll take to download the entire file, we have to divide the file size by the amount of the MB downloaded in one second. (This is assuming the download rate is constant, in the case it isn't constant, you would use calculus) This will find the total number of seconds needed to download the entire file.

We're essentially solving for t in the equation

$400.6 = 25.2t$

$t = \frac{400.6}{25.2} = \frac{2003}{126} = 15.897$

7 0

3 years ago

The average salary of all residents of a city is thought to be about $39,000. A research team surveys a random sample of 200 res

Rina8888 [55]

Answer:

$z=\frac{40000-39000}{\frac{12000}{\sqrt{200}}}=1.179$

$p_v =2*P(z>1.179)=2*[1-P(Z$

Step-by-step explanation:

Data given and notation

$\bar X=4000$ represent the average score for the sample

$s=12000$ represent the sample standard deviation

$n=200$ sample size

$\mu_o =39000$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu = 39000$

Alternative hypothesis : $\mu \neq 39000$

Compute the test statistic

The sample size is large enough to assume the distribution for the statisitc normal. The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$z=\frac{40000-39000}{\frac{12000}{\sqrt{200}}}=1.179$

Give the appropriate conclusion for the test

Since is a two tailed test the p value would be:

$p_v =2*P(z>1.179)=2*[1-P(Z$

Conclusion

If we compare the p value and a significance level given for example $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the true population mean for the salary not differs significantly from the value of 39000.

6 0

3 years ago