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Reil [10]
3 years ago
9

What is this me don't get it

Mathematics
2 answers:
MrMuchimi3 years ago
7 0
B. 19(44) = b
c. the farmer packs 836 oranges
Montano1993 [528]3 years ago
5 0
For step b. would be 44 divided by 19 = b for step c you can answwer seeing i gave you the equation and along with question a do things you know first then you might have the answers for the rest i hope this helps 
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Oliver earns $9 per hour. Write and solve an equation to find how many hours he must work to earn $315
natka813 [3]
Y=9x

315=9x

315/9=x

35=x
7 0
3 years ago
Kelly needs $125 to buy a dress for the dance. Her dad gave her five dollars for doing your chores and received $15 an hour to t
Debora [2.8K]
8 hours. 125 - 5 = 120. 120 / 15 = 8. Kelly will need to tutor for 8 hours minimum to buy the dress.
7 0
3 years ago
Please help!! 10 extra points
Igoryamba
HEY THERE !!

As we know that cotx= 1/tanx

cot36° = 1/tan36°

=>cot36°= 1/0.726543

=>so cot 36°= 1.376382

So correct answer is option D.


HOPR YOU LIKED.
7 0
3 years ago
100+500-355+287-311=?<br> A. 22<br> B. 222<br> C. 223<br> D. 931
Ainat [17]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 410 gram setting. It is
frozen [14]

Answer:

The decision rule for rejecting the null hypothesis is t < -1.721

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 410 gram setting. It is believed that the machine is underfilling the bags.

At the null hypothesis, we test if the mean weight of the bag is the desired value of 410, that is:

H_0: \mu = 410

At the alternate hypothesis, we test if the bag is underfilled, that is, the mean weight is below the desired value, so:

H_0: \mu < 410

Type of test:

As we test if the mean is less than a value, we have a left-tailed test.

We have the standard deviation for the sample, which means that the t-distribution is used.

We have 22 - 1 = 21 degrees of freedom, with a level of significance of 0.05.

Using a calculator, the critical value is t_c = -1.721

Determine the decision rule for rejecting the null hypothesis.

We reject the null hypothesis if the test statistic is less than the critical value, so the decision rule for rejecting the null hypothesis is t < -1.721

3 0
3 years ago
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