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Lunna [17]
3 years ago
5

The points A(3, 4), B(3, -2), C(-5, -2), and D(-5, 4) form rectangle ABCD. Which point is halfway between A and B?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
8 0
 Answer:  " (3,1)  is the point that is halfway between <em>A</em> and <em>B</em>. " 
__________________________________________________
Explanation:
__________________________________________________
We know that there is a "straight line segment" along the y-axis between
 "point A"  and "point B" ;  since, we are given that: 
___________________________________________
 1)  Points A, B, C, and D form a rectangle;  AND:
 
 2) We are given the coordinates for each of the 4 (FOUR points); AND:
 
 3) The coordinates of  "Point A" (3,4)  and "Point B" (3, -2) ; have the same "x-coordinate" value.
________________________________________________
  We are asked to find the point that is "half-way" between A and B.
________________________________________________
  We know that the x-coordinate of this "half-way" point is three.

We can look at the "y-coordinates" of BOTH "Point A" and "Point B".
___________________________
which are "4" and "-2",  respectively.

Now, let us determine the MAGNITUDE of the number of points along the "y-axis" between "y = 4" and y = -2 . 

The answer is:  "6" ;  since, from y = -2 to 0 , there are 2 points, or 2 "units" from y = -2 to y = 0 ;  then, from y = 0 to y = 4, there are 4 points, or 4 "units".

Adding these together,  2 + 4 = 6 units.
______________________________________________
So, the "half-way" point would be 1/2  of  6 units, or 3 units.
__________________________________________________
So, from y = -2 to y = 4 ;  we could count 3 units between these points, along the "y-axis".   Note, we could count "2" units from  "y = -2"  to "y = 0". 
Then we could count one more unit, for a total of 3 units;  from y = 0 to y = 1;  and that would be the answer (y-coordinate of the point).
______________________________________________
Alternately, or to check this answer, we could determine the "halfway" point along the "y-axis" from "y = 4" to "y = -2" ; by counting 3 units along the "y-axis" ; starting starting with "y = 4" ; note:  4 - 3 = 1 ; which is the "y-coordinate" of our answer; that is: "y = 1" ;  and the same y-coordinate we have from the previous (aforementioned) method above.
______________________________________________
We know the "x-coordinate" is "3" ; so the answer:
_________________________________________________
   " (3,1)  is the point that is halfway between <em>A</em> and<em> B </em>." 
__________________________________________________


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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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  T = 80 +65((95-65)/(145-65))^(t/30)

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Since the coffee in cup B cools twice as fast, it will cool to the same temperature (95°) in 15 minutes. In the next 15 minutes, the temperature difference will be reduced to (3/8)^2 of the original 80°, so will be 11.25°. That is, the temperature of cup B will be ...

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1. The distance between the perihelion and the aphelion is 116 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Step-by-step explanation:

Let us revise the equation of the ellipse is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where the major axis is parallel to the x-axis

  • The length of the major axis is 2a
  • The coordinates of the vertices are (± a , 0)
  • The coordinates of the foci are (± c , 0) , where c² = a² - b²

∵ The Sun is located at a focus of the ellipse

∴ The sun located ate c

∵ The perihelion is the point in a planet’s orbit that is closest to the

   Sun ( it is the endpoint of the major axis that is closest to the Sun )

∴ The perihelion is located at the vertex (a , 0)

∵ The closest Mercury comes to the Sun is about 46 million miles

∴ The distance between a and c is 46 million miles

∵ The aphelion is the point in the planet’s orbit that is furthest from

   the Sun ( it is the endpoint of the major axis that is furthest from

   the Sun )

∴ The aphelion is located at the vertex (-a , 0)

∵ The farthest Mercury travels from the Sun is about 70 million miles

∴ The distance from -a to c is 70 million miles

∴ The distance between the perihelion and the aphelion =

   70 + 46 = 116 million miles

1. The distance between the perihelion and the aphelion is 116 million miles

∵ The distance between the perihelion and the aphelion is the

  length of the major axis of the ellipse

∵ The length of the major axis is 2 a

∴ 2 a = 116

- Divide both sides by 2

∴ a = 58

∴ The distance from the center of Mercury’s elliptical orbit to the

   closest end point to the sun is 58 million miles

∵ The distance between the sun and the closest endpoint is

   46 million miles

∴ The distance from the center of Mercury’s elliptical orbit and

   the Sun = 58 - 46 = 12 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

∵ The major axis runs horizontally

∴ The equation is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

∵ a = 58

∵ c is the distance from the center to the focus of the ellipse

∴ c = 12

∵ c² = a² - b²

∴ (12)² = (58)² - b²

- Add b² to both sides

∴ (12)² + b² = (58)²

- Subtract (12)² from both sides

∴ b² = (58)² - (12)² = 3220

- Substitute these values in the equation

∴ \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

The eccentricity (e) of an ellipse is the ratio of the distance from the

center to the foci (c) and the distance from the center to the

vertices (a) ⇒ e=\frac{c}{a}

∵ c = 12

∵ a = 58

∴ e=\frac{12}{58} = 0.207

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

If the eccentricity is zero, it is not squashed at all and so remains a circle.

If it is 1, it is completely squashed and looks like a line

∵ The eccentricity of the ellipse is 0.207

∵ This number is closed to zero than 1

∴ The shape of the ellipse is near to the shape of the circle

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Learn more:

You can learn more about conics section in brainly.com/question/4054269

#LearnwithBrainly

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