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Dominik [7]
3 years ago
14

What is the length of ef in the right triangle below?

Mathematics
2 answers:
monitta3 years ago
8 0

Answer:

<h2><u><em>24</em></u></h2>

Step-by-step explanation:

The Pythagoras theorem formula states that in a right triangle ABC, the square of the hypotenuse is equal to the sum of the square of the other two legs. If AB, BC, and AC are the sides of the triangle, then: BC2 = AB2 + AC2​. While if a, b, and c are the sides of the triangle, then ​c2 = a2 + b2.

√(25²-7²) =

√(625-49)=

√576=

24

katrin2010 [14]3 years ago
3 0

Answer: A

Step-by-step explanation:

Using pythagoras;

25 = \sqrt{7^{2}+ x^{2} }\\25^{2}=7^{2} +x^{2}   \\625 = 49 +x^{2} \\576 = x^{2} \\x = 24

Please give me a brainliest answer

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The area of a room is 26.025 m sqaure. If its length is 12.5m . find the breadth of the room​
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Answer:

2.082.

Step-by-step explanation:

Solution,

Given,

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Length ( L ) = 12.5 m.

Now,

Breadth ( B ) = Area ÷ Length.

= 26.025 ÷ 12.5

= 2.082.

Thus, The breadth of the room is 2.082 m.

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Find the geometric mean between 20 and 5
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Consider the following portion of an electric circuit with three relays. Current will flow from point a to point b if there is a
Svetradugi [14.3K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a
NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

According to the statement

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So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

And then substitute the values in it then

Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

This is the probability.

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Learn more about probability here

brainly.com/question/24756209

#SPJ4

7 0
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The outside of a picture frame measures 14 in and 20 in 196in^2 of the picture shows find the thickness of the frame
LuckyWell [14K]
The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width. 
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We are given that the area is only equal to 192 in². We subtract this value from the computed area.
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This area is equal to the area of the hollow space inside the frame. That is equal to,
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      length = 14 in - 2x

The area,
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Simplify the right hand side of the equation.
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Divide the equation by 4,
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Transposing,
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The factors of the equation is 58.2. 

Thus, the thickenss is equal to 58.2 in
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4 years ago
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