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prisoha [69]
2 years ago
12

Can u solve two questions. .. Mark brilliant student​

Mathematics
1 answer:
kolbaska11 [484]2 years ago
6 0

sorry I don't know if you ask to other sure I think they will tell you ans

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Which expression is equivalent to 4/5 x 120? zoom in to see clearly!
drek231 [11]

Answer:

Which expressions is equivalent to 4/5*120= 96

B 4*120 divided by 5=96

Step-by-step explanation:

The second question is 589 4/5

(5*100)+(8*10)+(9*1)+(2*1/10)+(6*1/100)= 589 4/5

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2 years ago
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An archaelogist in Turkey discovers a
AURORKA [14]

Answer:

I am condused too?//

Step-by-step explanation:

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3 years ago
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What is the best estimate for the length of a bike
castortr0y [4]
<span>The average length of a bike (including the length of both wheels) is about 68 inches.For finding the true answer we must follow the following convertion rule: 1 inch is equivalent to 0.02 yard, so 68 inches equal to 1.88 yards. Consequently, the value nearest 1.88 yards is 1.5 yards, so the answer is the choice A: 1.5 yards. </span>
8 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
I need answer fast..
Novosadov [1.4K]

Answer:

a. Portrays the case of two triangles being equal if two angles and the line between them are equal

b. The case of two triangles being equal when two of their lines are equal, compared 2 by 2 and the angles between them are equal

c. The case of two triangles being equal when all lines are equal, compared 2 by 2

5 0
3 years ago
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