Answer:
5.83 blocks away from his home
Step-by-step explanation:
If he travels 5 blocks south and 3 blocks west, the distance from his house considered along with the distances travelled gives a right angled triangle whose opposite side and adjacent sides are the distances travelled north and west.
The distance from his house after moving 3 blocks west is the hypotenuse side. As such, the distance may be computed using Pythagoras' theorem. Let the distance from his house be G
G^2 = 5^2 + 3^2
G^2 = 25 + 9
= 34
G = √34
=5.83
John is 5.83 blocks away from his home
CosA=(21^2+23^2-25^2)/2*21*23
cosA=345/966
A=cos^-1(345/966)
A=69.08
Answer:
y = -2x -3
Step-by-step explanation:
- the altitude trough F is a perpendicular line to the line DE
- find slope of line DE
D ( x2 = -5, y2 = -1); E (x1 = 3, y1 = 3)
slope m = (y2-y1) / (x2-x1) = (-1-3) / (-5-3) = -4/ -8 = 1/2
-find equation of the altitude trough F
lines that are perpendicular have the slope negative reciprocal (negative reciprocal of 1/2 is -2)
y= -2x +b , for point F(1, -5)
-5 = -2*1 +b, add 2 to both sides
-5 +2 = b, combine like terms
-3 =b
equation of the altitude trough F is y = -2x -3
Given,
∠AOE = 30°
∠DOB = 40°
So, ∠EOD = 180 - (30+40) [angles on a straight line]
= 180 - 70
= 110
∠EOD = ∠COF [ vertically opposite angle]
∴ ∠COF = 110°
Hey! Your answer would be x = 6a/5
