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2 years ago

Which of the following is the usually first step when using a general strategy for solving equations with fractions?

Mathematics

1 answer:

tester [92]2 years ago

4 0

Answer:

A. multiply both sides by the LCD

Step-by-step explanation:

It helps cancel out fractions, making it easier to solve the equations

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What is the length of the hypotenuse of a right triangle with legs of 50 ft. and 120 ft. ?

MrMuchimi

Answer: 130 ft

Step-by-step explanation:

a^2 + b^2 = c^2

Where a and b are the legs that form the right angle and c is the hypotenuse (the side directly opposite of the right angle)

50^2 + 120^2 = c ^2

2,500 + 14,400 = c^2

16,900 = c^2

Take the square root of 16,900 to get c.

C = 130

Hypotenuse length is 130

6 0

3 years ago

What is the surface area of a rectangular prism that has these dimensions? 2 cm x 3 cm x 5 cm?

algol [13]

30 centimeters cubed is the answer

8 0

3 years ago

carmela cut a cake into 12 equal-sized pieces. She ate 2/12 of the cake and her brother ate 3/12 of the cake.What fraction of th

Rzqust [24]

1/12 of the cake is left for carmela to eat

6 0

2 years ago

Read 2 more answers

5√28+ √63<br> please simplify no exponents please

zaharov [31]

Answer:

34.3948

Step-by-step explanation:

$5\sqrt{28} +\sqrt{63} = 13\sqrt{7} = 34.3948$

3 0

3 years ago

Read 2 more answers

From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle

Mariulka [41]

Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

So, the height of the building = ( x + 8.20 ) meters,

Now, 1 degree = 60 minutes,

⇒ $1\text{ minute } =\frac{1}{60}\text{ degree }$

$20\text{ minutes }=\frac{20}{60}=\frac{1}{3}\text{ degree}$

$50\text{ minutes }=\frac{50}{60}=\frac{5}{6}\text{ degree}$

By the below diagram,

$tan ( 12^{\circ} 50') = \frac{8.20}{y}$

$tan(12+\frac{5}{6})^{\circ}=\frac{8.20}{y}$

$tan (\frac{77}{6})^{\circ}=\frac{8.20}{y}$

$\implies y=\frac{8.20}{tan (\frac{77}{6})^{\circ}}$

Now, again by the below diagram,

$tan (31^{\circ}20')=\frac{x}{y}$

$tan(31+\frac{1}{3})=\frac{x}{y}$

$\implies x=y\times tan(\frac{94}{3})=\frac{8.20}{tan (\frac{77}{6})^{\circ}}\times tan(\frac{94}{3})^{\circ}=21.9142943216\approx 21.91$

Hence, the height of the building = x + 8.20 = 30.11 meters (approx)

8 0

3 years ago