Question

when n basketball uniforms are purchased , the cost , C , of each uniforms is given by the equation C=40n+260/n. if the cost of each uniform was $60 , how many uniforms were purchased?

Answer 1

Hello!

As you can see, C is the cost of each uniform. This would give us the equation below, if each uniform was $60.

60=40n+260/n

Let's multiply both sides by n.

60n=40n+260

Now, let's subtract 40n from both sides.

20n=260

We divide both sides by 20.

n=13

Therefore, 13 uniforms were purchased.

I hope this helps!

Answer 2

Answer: 13 uniforms.

Step-by-step explanation: To solve the given problem we need to calculate the number of basketball uniforms that were purchased if the cost of each uniform was $60, using the given equation:

C=$C=\frac{40n-260}{n}$

substituting C=60:

$60=\frac{40n+260}{n}$

multiplying both sides by n:

60n=40n+260

60n-40n=260

20n=260

n=260/20

n=13.

13 uniforms were purchased.