This question is incomplete, the complete question is;
Determine if the described set is a subspace. Assume a, b, and c are real numbers.
The subset of R³ consisting of vectors of the form
, where abc = 0
- The set is a subspace
- The set is not a subspace
Answer:
Therefore; The set is not a subspace
Step-by-step explanation:
Given the data the question;
the subset R³;
S = {
, where abc = 0 }
we know that a subset of R³ is a subspace if it stratifies the following properties;
- it contains additive identity
- it is closed under addition
- it is closed under scales multiplication
Looking at the properties, we can say that it is not a subspace
As;
u =
∈ S and v =
∈ S
As 1×1×0=0 0×1×1=0
But u+v =
∉ S as 1×2×1 ≠ 0
Hence, it is not closed under addition.
Therefore; The set is not a subspace
Answer:
4
Step-by-step explanation:
7x = x² - 8
=> x² - 7x - 8 = 0
use quadratic formula:
a = 1, b = -7, c = -8
x =
<em>(pls ignore the "A" I don't know why it's showing up)</em>
=> x =
=> x = 
=> x =
= 4 or
= -5 <em>(the answer is only 4 since it's asking for the positive solution)</em>
Answer:
<em>-21 and 4</em>
Step-by-step explanation:
They multiply to a negative number, so you need a positive number and a negative number.
We can say that the length of line segment Y'Z' will increase by a scale factor of 2.