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jarptica [38.1K]
3 years ago
12

(2x-7)^2 subtracted from 2

Mathematics
1 answer:
weqwewe [10]3 years ago
4 0

Write out the expression 2 - (2x-7)^2.  That's it.

But if you want to go further and remove the parentheses, first expand (2x-7)^2:   (2x-7)^2 = 4x^2 - 28x + 49,

and then subtract this result from 2:

2 - (4x^2 - 28x + 49) (It's important to use parentheses here)

Now, following the distributive property of multiplication, remove the parentheses:

2 - 4x^2 + 28x - 49

Combining the constants, we get the final answer:  - 4x^2 + 28x - 47

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Please help with simple probability question. Extra points & brainliest. Thanks in advance.
kodGreya [7K]
The answer is B) 1/3.

There are 6 faces on a rectangular prism, each of which is a rectangle.  

The area of the front and back is given by 25(8) = 200 sq. cm.
The area of the bottom and top is given by 25(4) = 100 sq. cm.
The area of the right and left is given by 4(8) = 32.

There are 2 faces out of 6 with an area that is not a multiple of 100; 2/6 = 1/3.
3 0
3 years ago
A.
Dovator [93]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
The trajectory of a flying saucer is given by the vector function r(t) = (5 sin(t))i + (5 cos(t))j + 12tk for t ≥ 0 where coordi
Kipish [7]

Answer:

t0 = 2

Step-by-step explanation:

r' = <5cost,-5sint,12>

ds = \sqrt{25cos^{2}t+25sin^{2}t+12^2} = \sqrt{25+144} = 13 dt

So, we want

\int\limits^x_0 {13} \, dt = 26

8 0
3 years ago
Which percent is equal to 0.35?
Rama09 [41]

Answer:

35%

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
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