Question

Plz answer its easy math.

Answer 1

$\text{Use}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}\\-----------------------\\\\\dfrac{3^{-8}}{3^{-4}}=3^{-8-(-4)}=3^{-8+4}=\underbrace{\boxed{3^{-4}}}_{\boxed{B.}}=\underbrace{\boxed{\dfrac{1}{3^4}}}_{\boxed{E.}}\\\\Answer:\ \boxed{B.\ and\ E.}$

Answer 2

Greetings!

Answer:

B and E

Step-by-step explanation:

The rules of indicies states:

$x^{a}$ ÷$x^{b}$ = $x^{a-b}$

So $3^{-8}$ ÷  $3^{-4}$ =  $3^{-8 - - 4}$ =  $3^{-4}$

So that means B is one of the correct answers.

To find the other correct value, you can divide the two fractions as stated in the question:

$3^{-8}$ by $3^{-4}$ = $\frac{1}{81}$

81 is equivalent to 3⁴

So that means E is also correct.

Hope this helps!