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3 years ago

12

Plz answer its easy math.

2 answers:

Basile [38]3 years ago

5 0

$\text{Use}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}\\-----------------------\\\\\dfrac{3^{-8}}{3^{-4}}=3^{-8-(-4)}=3^{-8+4}=\underbrace{\boxed{3^{-4}}}_{\boxed{B.}}=\underbrace{\boxed{\dfrac{1}{3^4}}}_{\boxed{E.}}\\\\Answer:\ \boxed{B.\ and\ E.}$

Serga [27]3 years ago

3 0

<h2>Greetings!</h2>

Answer:

B and E

Step-by-step explanation:

The rules of indicies states:

$x^{a}$ ÷ $x^{b}$ = $x^{a-b}$

So $3^{-8}$ ÷ $3^{-4}$ = $3^{-8 - - 4}$ = $3^{-4}$

So that means B is one of the correct answers.

To find the other correct value, you can divide the two fractions as stated in the question:

$3^{-8}$ by $3^{-4}$ = $\frac{1}{81}$

81 is equivalent to 3⁴

So that means E is also correct.

<h2>Hope this helps!</h2>

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Answer:

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Step-by-step explanation:

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BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

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Now , by using the above formula , 5th term can be written as ;

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${: \implies \quad \sf T_{2}= T_{1}+(2-1)d}$

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${: \implies \quad \sf T_{2}= 8-3}$

${: \implies \quad \bf \therefore \: T_{2}= 5}$

Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

${: \implies \quad \sf T_{3}= 8 +2d}$

${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

${: \implies \quad \sf T_{4}= T_{1}+(4-1)d}$

${: \implies \quad \sf T_{4}= 8 +3d}$

${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

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2 years ago

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Answer:

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