Answer:
The answer is 3/4 and -1/2

Possible values are
x=1,y=11
x=2,y=8
x=3,y=5
x=4,y=2
Answer:
its to long for me
Step-by-step explanation:
Answer:
If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).
Then at t = 20:
y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}
Step-by-step explanation:
The answer is: D) 115
The explanation is shown below:
1. You have that the frequency with which a cricket chirps varies directly with the temperature, which you can express it as following:

Where
is the frequency with which a cricket chirps,
is the temperature and
is the constant of proportionality.
2. If the cricket chirps 100 times per minute in 80° weather, you can calculate
as below:

3. Therefore, the frequency in 92° weather is:
