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3 years ago

12

Marco bounces a basketball 45 times in 60 seconds.at the rate approximately how many times will Marco bounce the ball 150 secon

ds?

1 answer:

worty [1.4K]3 years ago

4 0

Answer:

Approximately : 135

Step-by-step explanation:

60sec x 3 = 180sec

45 x 3 = 135

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An IQ test is designed so that the mean is 100 and the standard deviation is 12 for the population of normal adults. Find the sa

Julli [10]

Answer:

Step-by-step explanation:

Given that IQ mean is 100 and std dev = 12 for normal adults

$Confidence level =90%\\Z critical value = 1.645\\Margin of error = 2\\Margin of error = 1.645* std error =2\\Std error = 1.216$

Std error = $\frac{12}{\sqrt{n} } =1.216$

$n=(\frac{12}{1.216} )^2 =97.38$

i.e. sample size should be atleast 97

The required sample size is 97.

This is reasonable as this is greater than 30

Yes. This number of IQ test scores is a fairly large number.

5 0

3 years ago

Choose the imensions that represen this rectlangl

almond37 [142]

Answer:B

Step-by-step explanation:I hope it help

3 0

2 years ago

- 7h + 2(-4h +5) > -4h +1 +10. Solve for h

navik [9.2K]

Hello.

-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h

Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.

-7h - 8h + 10 > -4h + 11

Add like terms.

-15h + 10 > -4h + 11

Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.

Subtract 10 from both sides. Then, add 4h to both sides.

-15h + 4h > 11 - 10

Simplify.

-h > 1

Divide both sides by -1.

However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <

-h ÷ -1 < 1 ÷ -1

h < -1

6 0

3 years ago

Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min

leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2}$ .

First, we simplify the expression in the numerator of the fraction.

$3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72$

Now, we obtain

$12(x^2-x-6) = 12(x+2)(x-3)$

and the fraction is transformed into

$\frac{3(2x-1)^2 - 75}{x+2} = \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)$

Therefore, the following limit is

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2} 12(x-3) = 12 \lim_{x \to -2} (x-3)$

You can plug in $-2$ in the equation, hence

$12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60$

6 0

3 years ago

Simplify the expression 2.75j + 2.25 - 1.5j + 3

Katarina [22]

1.25j+5.25 would be the answer. just combine like terms

3 0

3 years ago