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miskamm [114]
3 years ago
9

After five years of earning interest at an annual rate of 4%, an investment has earned $1,200 in interest. Determine the amount

of the initial investment. Show all work for full credit.
Mathematics
2 answers:
Andru [333]3 years ago
6 0
P=I÷rt
P initial investment ?
I interest earned 1200
R interest rate 0.04
T time 5 years

P=1,200÷(0.04×5)
P=6,000

Hope it helps
Evgen [1.6K]3 years ago
5 0

Answer:

The amount of the initial investment is $ 6000.

Step-by-step explanation:

Given: After five years of earning interest at an annual rate of 4%, an investment has earned $1,200 in interest.

We have to find the amount of the initial investment.

We know,

\text{Simple interest}=p\times r\times t

Where P is initial investment

r is rate of interest

t is time period.

Given : Simple interest = $ 1200

Rate = 4 % =0.04

Time = 5 years

Substitute, we get,

1200=P\times 0.04\times 5

Solve for P, we have,

Divide both side by 0.04 × 5  , we have,

\frac{1200}{0.04\times 5}=P

Simplify, we get ,

P = $ 6000

Thus, The amount of the initial investment is $ 6000.

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Answer:

3(7+5)

Step-by-step explanation:

21+15

Each term is divisible by 3

3*7 +3*5

3(7+5)

6 0
3 years ago
What is 6 divided by 7/9
Hunter-Best [27]

Answer:

54/7

Step-by-step explanation:

  1. Use the KCF method - Keep, Change, Flip
  2. 6 divided by 7/9 is just 6/1 divided by 7/9
  3. You can keep 6/1 as the way it is
  4. Next, you change the sign from division to multiplication
  5. Lastly, you flip 7/9 to 9/7
  6. It will now change from 6 divided by 7/9 to 6/1 x 9/7
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3 years ago
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720 m²

Step-by-step explanation:

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5 0
1 year ago
With Obesity on the rise, a Doctor wants to see if there is a linear relationship between the Age and Weight and estimating a pe
Romashka [77]

Answer:

112.569 ( D )

Step-by-step explanation:

Applying the estimated Regression Equation

y = b1X1 + b2X2 + a

b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884

b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925

a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252

y = 0.939X1 + 0.309X2 + 31.733

For x1 ( age ) =39, and  x2(weight) =143

y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569

where

Sum of X1 = 981

Sum of X2 = 3102

Sum of Y = 2388

Mean X1 = 61.3125

Mean X2 = 193.875

Mean Y = 149.25

attached is the Tabular calculation of the required values needed for estimated regression equation

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2 years ago
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