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natta225 [31]
3 years ago
8

A town council wants to estimate the proportion of residents who are in favor of a proposal to upgrade the computers in the town

library. A random sample of 100 residents was selected, and 97 of those selected indicated that they were in favor of the proposal. Is it appropriate to assume that the sampling distribution of the sample proportion is approximately normal?A. No, because the sample is not large enough to satisfy the normality conditions.
B. No, because the size of the population is not known.
C. Yes, because the sample was selected at random.
D. Yes, because sampling distributions of proportions are modeled with a normal model.
E. Yes, because the sample is large enough to satisfy the normality conditions.
Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer: E. Yes, because the sample is large enough to satisfy the normality conditions

Step-by-step explanation:

The Central Limit Theorem states that the sampling distribution of the sample means approaches a normal distribution as the sample size gets larger. The requirement is usually pegged at when number of samples is greater than or equal to 30. From the information given, sample size = 100

Therefore, it appropriate to assume that the sampling distribution of the sample proportion is approximately normal

E) because the sample is large enough to satisfy the normality conditions

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Answer:

The correct answer is option (C)-0.245 = 2.160(0.205)

Step-by-step explanation:

Solution

Given that:

The slope = - 0.245

The size sample = n = 15

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The confidence level = 95

The Significance level= α = (100- 95)% = 0.05

Now,

The freedom of degree = n-2 = 15 -2= 13

Thus,

the critical value = t* = 2.16

By applying Excel = [TINV (0.05, 13)]

The Margin of error is = t* (standard error)

=2.16 *0.205

= 0.4428

8 0
2 years ago
Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I
Elden [556K]

Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

Security\ A = 2\ mins+ \frac{20}{60}\ min

Security\ A = 2\ mins+ \frac{1}{3}\ min

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\ mins, 40\ secs

Security\ B = 1\ mins+ 40\ secs

Security\ B = 1\ mins+ \frac{40}{60}\ min

Security\ B = 1\frac{2}{3}\ min

So, we have:

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...

Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

Time = 11\frac{2}{3}\ min

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4 0
3 years ago
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aniked [119]

Answer:

<h2>x=52</h2>

Basic fact:

<em>angles in a point add up to 360</em>

Step-by-step explanation:

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4 0
2 years ago
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yaroslaw [1]

Answer:

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Step-by-step explanation:

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Factor out the R

R(T-S)=-TS

Divide by (T-S) to isolate R

R = \frac{-TS}{(T-S)}

5 0
3 years ago
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attashe74 [19]
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12 ÷ 2.45 ≈ 4.90 gallons.

You get roughly 4.90 gallons.
6 0
2 years ago
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