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harkovskaia [24]
3 years ago
14

Calculate dy/dx You need not expand your answer. y=3x^2-9x+13/2x+4 ...?

Mathematics
1 answer:
grandymaker [24]3 years ago
8 0
The solution to the problem is as follows:

The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know} 

let f(x)=9x +13 and g(x)=2x+4 
<span>
f'(x)=9 and g'(x)=2 </span>
<span>
therefore just substitute the equations in. </span>
<span>
y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2)) 
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer:

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Step-by-step explanation:

To find the angle we need to use the following equation:

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Where:

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At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

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\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

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