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4 years ago

8

X^3+x²-36 Find all real zeros.

1 answer:

Harman [31]4 years ago

4 0

Answer: x=3

Step-by-step explanation:

To find the zeros, you want to first factor the expression.

x³+x²-36

(x-3)(x²+4x+12)

Now that we have found the factors, we set each to 0.

x-3=0

x=3

Since x²+4x+12 cannot be factored, we can forget about this part.

Therefore, the zeros are x=3. You can check this by plugging the expression into a graphing calculator to see the zeros.

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3 years ago

What value for C will make the expression a perfect square trinomial x2-7x+c

Tom [10]

Answer:

The value of c is 12.25

Step-by-step explanation:

we know that

A perfect square trinomial is of the form

$(x-a)^{2}=x^{2}-2ax+a^{2}$

In this problem we have

$x^{2}-7x+c$

so

equate the equations

$x^{2}-7x+c=x^{2}-2ax+a^{2}$

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<u>Solve the equation A</u>

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<u>Solve the equation B</u>

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7 0

3 years ago

Read 2 more answers