3 years ago

X^3+x²-36 Find all real zeros.

Mathematics

1 answer:

Harman [31]3 years ago

4 0

Answer: x=3

Step-by-step explanation:

To find the zeros, you want to first factor the expression.

x³+x²-36

(x-3)(x²+4x+12)

Now that we have found the factors, we set each to 0.

x-3=0

x=3

Since x²+4x+12 cannot be factored, we can forget about this part.

Therefore, the zeros are x=3. You can check this by plugging the expression into a graphing calculator to see the zeros.

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