$87.00 divided by 5 can u divide pls

Mathematics

1 answer:

Illusion [34]4 years ago

6 0

$87.00/5 is $17.4 dollars

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You synthetic division to find P(3) for p(x)=x^4-6x^3-4x^2-6x-2

klio [65]

By the polynomial remainder theorem, the remainder upon dividing $p(x)$ by $x-3$ will be the value of $p(3)$ .

... | 1 ... -6 ... -4 ... -6 .... -2
3. | .. ... 3 ... -9 ... -39 .. -135
--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137

So you have

$\dfrac{x^4-6x^3-4x^2-6x-2}{x-3}=x^3-3x^2-13x-45-\dfrac{137}{x-3}$

which means $p(3)=-137$ .

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3 years ago

What is the 9th term in a geometric sequence with a common ratio of 2 and a first term of 3

Artyom0805 [142]

Answer: 768

Step-by-step explanation:

Just multiply 2 by the first term (3) until u get to the 9th term

So 1.. 3*2= 6

2.. 6*2=12

3.. 12*2= 24

& so forth

So the 9th term is 768

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3 years ago

Eliminate the parameter,t, in the parametric equation, x=6cos t, and y =3 sin t

german

X = 6 cos(t)
y = 3 sin(t)

we can rewrite these equations as:

$\frac{x}{6}=cost(t) \\ \\ \frac{y}{3} =sin(t)$

Taking squares of both equations we get:

$( \frac{x}{6})^{2}=sin^{2} (t) \\ \\ 
( \frac{y}{3})^{2}=cos^{2}(t)$

Adding both the equations, we get:

$\frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=sin^{2}(t)+cos^{2}(t) \\ \\ 
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3 years ago

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Mrac [35]

Answer:

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