The answer for the first one is 12. 15% of 80 is 12. The second one I can’t answer because it is not very clear and is cut off
Answer:
Step-by-step explanation:
Think of of this as a function in which the number of pounds is a function of the number of hours. Each piece of given information is a point. Each point has the format (x, y) = (hours, pounds), where hours is x and is the independent variable, and pounds is y and is the dependent variable.
You have two points (4.5, 1445) and (7, 2320). First find the slope of the line that passes through those two points. Use the slope formula,
m = (y2 - y1)/(x2 - x1).
Then using the slope and the point-slope equation of a line, find the equation of the line. The point-slope equation of a line is
y - y1 = m(x - x1),
where m = slope, and the point is (x1, y1).
Try it. If you have questions or need extra help, just comment.
Step-by-step explanation:
x = -10, y = 10
y= -4x+4
m1×m2 = -1
-4 × m2 = -1
m2 = 1/4
y-y1 = m(x-x1)
y-10 = 1/4(x+10)
y-10 = 1/4x +10/4
(×4)
4y-40=x+10
4y=x+50
x-4y+50=0
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
7 + 4
Step-by-step explanation:
note that 
× = a
Given
(2 + )² = (2 + )(2 + )
Each term in the second factor is multiplied by each term in the first factor, that is
2(2 + ) + (2 + ) ← distribute both parenthesis
= 4 + 2 + 2 + 3 ← collect like terms
= 7 + 4
