1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Korolek [52]
3 years ago
9

Confused on question in screenshot.

Mathematics
1 answer:
Bogdan [553]3 years ago
5 0

Answer:

The right answer is the second option, 9,747.

Step-by-step explanation:

EG^2 = DG*FG \\ EG^2 = 5*14 \\ EG = \sqrt{70}

Now let's find DE (Pythagorean theorem).

DE^2 = DG^2+EG^2\\ DE = \sqrt{25+70} \\ DE = \sqrt{95}

\sqrt{95} =9,7467... = 9,747

You might be interested in
Lexi bulletin board is 40 centimeters wide,and her photos are 12 centimeters wide. What combinations of ribbons and photos will
Mrac [35]

Three would fit cause 3 times 12 is 36 and 4 times 12 is 48 which would be too big

8 0
3 years ago
A bowl is in the shape of a hemisphere (half a sphere) with a diameter of 8 inches. Find the volume of the bowl. Use 3.14 for pi
gayaneshka [121]

Answer: 267.947 (or 267.95) inches^3

Step-by-step explanation:

The formula for the volume of a sphere is \frac{4}{3}\pi r^{3}.

To find your radius (r), divide the diameter of 8 inches by 2. <em>The radius is 4 inches.</em>

Plug in your numbers to the volume equation to get \frac{4}{3} (3.14)(4^3). The first step is to cube 4 (4*4*4) to get <em>64</em>. Now your equation is \frac{4}{3}(3.14)(64).

Multiply 3.14 and 64 to get <em>200.96</em>. The equation is now \frac{4}{3}(200.96) or \frac{4}{3} * \frac{200.96}{1}.

Multiply the numerators (4 * 200.96) and denominators (1 * 3) to get a final equation of \frac{803.84}{3}.

Finally, divide 803.84 by 3 to get the final answer of 267.947 in^3.

8 0
3 years ago
Paul earned a salary of $926.35 and a commission of $136.15. How much did he earn in all?
Natasha2012 [34]
<span>The total of his income was 926.35 plus 136.15 which is $ 1062.50 in all.

P.S

Happy to help you again ^-^
</span>
8 0
3 years ago
If a sponsored link was delivered 100 times and 10 people clicked on it, then the number of impressions is 100, the number of cl
Rudik [331]

Answer:

Option A.

Step-by-step explanation:

It is given that a sponsored link was delivered 100 times and 10 people clicked on it.

Number of impressions = 100

Number of clicks = 10

The formula for click-through-rate (CTR) is

CTC=\dfrac{\text{Total measured clicks}}{\text{Total measured impression}}\times 100

CTC=\dfrac{10}{100}\times 100

CTC=10

The click-through-rate (CTR) would be 10%. Therefore, the correct option is A.

7 0
3 years ago
PLZZZ HELPPP, IF NOT 100% SURE PLZ DONT ANSWER…BRAINLIEST TO FIRST AND CORRECT ANSWER, THX TO SECOND AND CORRECT ANSWER
Vladimir79 [104]

Answer:

2 batches

Step-by-step explanation:

We can divide 7 1/2 by 3 3/4 to get 2, so the factory made 2 batches of granola bars yesterday.

5 0
3 years ago
Other questions:
  • Complete the ordered pairs of two points on a line with a greater rate of change than the given linear function
    5·1 answer
  • a bag with 9 marbles is shown a marble is chosen from the bag at random. what are the odds in favor of choosing a black marble
    13·1 answer
  • Which number is a factor of 24, but not a multiple of 2
    11·2 answers
  • Which of the following numbers listed below are solutions to the equation?
    7·1 answer
  • Mr. Edelstein has driven 12 miles in 15 minutes. What is his speed in miles per hour?
    13·1 answer
  • Which number is bigger 2.04, 2, 2.4,2.07, 2.24
    10·2 answers
  • A lines passes through the points (-4, 7) and (5, -8). What is the slope of the line?
    13·1 answer
  • Given f(x) = 3x – 1, solve for x when f(x) = -7.
    13·2 answers
  • If x =- 5, which expression is equivalent to - 40k – x)?
    5·1 answer
  • The product of ages of Hasni and Alia is 32 years. Hasni is 4 years older than Alia. How old are Hasni and Alia?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!