9. Hannah solved an equation as shown below.

Please help, photo attached.

steposvetlana [31]

The zeroes of the polynomial functions are as follows:

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

<h3>What are the zeroes of a polynomial?</h3>

The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.

The polynomials are given as follows:

f(x) = 2x(x - 3)(2 - x)

f(x) = 2(x - 3)²(x + 3)(x + 1)

f(x) = x³(x + 2)(x - 1)

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2

For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1

For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.

Learn more about polynomials at: brainly.com/question/2833285

#SPJ1

5 0

2 years ago

1. What is the slope between the points (2,-5) and (8,3)? * Show work please

hjlf

Answer:

$\sf m = \dfrac{4}{3}$

Step-by-step explanation:

Given, $\sf (x_1, ~ y_1)$ = (2, -5) and $\sf (x_2, ~ y_2)$ = (8, 3)

The slope formula is, $\sf m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\sf m = \dfrac{3 - (-5)}{8 - 2}$

$\sf m = \dfrac{8}{6}$

$\bf m = \dfrac{4}{3}$

6 0

2 years ago

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base

kaheart [24]

Answer:

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

__

We expect your answer is supposed to be Step 4.

7 0

3 years ago

Let y- 2t+ 5 be a linear function representing the distance from home for an ant tminutes after starting out from a location nea

blondinia [14]

The 5 represents the starting distance from home. In other words, when t = 0, the value of y is y = 5. Replacing t with 0 leads to this y value. This is the y intercept. So at time 0 minutes, the ant is 5 units from home. Replace "units" with whatever units you happen to be using.

8 0

3 years ago

Task 4 Task 다. Given: m

Mariulka [41]

Answer:

where the choices?

Step-by-step explanation:

7 0

3 years ago