One way to solve this is to use Pythagorean theorem: the square of one leg of triangle plus square of other leg of the triangle equals c the hypotenuse (longest side of triangle). You might see this as the formula a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.
In this case, the legs are 3√2 and the hypotenuse is h.
Using the formula:
(3√2)² + (3√2)² = h²
18 + 18 = h²
h = 6
The other way to do this is with trigonometric angles.
Remember cosine is adjacent over hypotenuse.
cos(45°) = (3√2) / h
h = (3√2) / cos(45°)
h = 6
No he's not correct
<span>(3 – 6y2)(y2 + 2)
= 3(y2) -6(y2)(y2) - 6y2(2) </span>+ 3(2)<span>
= 3y2 -6y4 - 12y2 </span>+ 6 <span>
= -6y4 - 9y2 +6</span>
The picture in the attached figure
we have
arc XV = 68°∠YUV = 36°
we know that
The measure of the external angle is the semidifference of the arcs that it covers.
therefore
∠YUV =[arc VY-arc XV]/2
arc VY=[2*∠YUV]+arc XV----------> [2*36]+68---------> 140°
the answer is
the measure of arc VY is 140°
Answer:
15f^2
Step-by-step explanation:
multiply lenghtxwidth
always make sure to square your answer when doing area