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galben [10]
3 years ago
8

Someone answer this :)

Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

x=29.9 degrees

Step-by-step explanation:

Sides we are given: x and side length of 92.

Angle we are given: angle of measure 18.

Relative to the angle we are given, we have the opposite and adjacent sides, so we use TOA, as O is opposite and A is adjacent.

Tangent 18= x/92

Tangent 18 (92)=x

x=29.9 degrees

ANTONII [103]3 years ago
6 0

Answer:

29.9 to one decimal place

Step-by-step explanation:

To work out X you can find the missing angle by doing;

180 - (90 + 18) = 72

Then use Sine rule to work out X;

x =  \frac{92}{ \sin(72)}  \times  \sin(18) \\ x = 29.89261.....

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Lf g(x) = x3 - 5 and h(x) = 2x - 2, find g(h(3)).
White raven [17]

Answer: g(h(3)) = 59

Step-by-step explanation:

Well if its x^3 I assume it is because you wrote other coefficients before the variable.

2(3) - 2 = 6-2 = 4

So 4 is the x input for h(x)

4^3 -5 = 64-5 = 59

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0.0057 in scientific notation
Gelneren [198K]

Answer:

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Step-by-step explanation:

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klasskru [66]
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2 years ago
The sum of three numbers is 8. The third is 9
Ierofanga [76]

Answer:

→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>

→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>

→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>

Step-by-step explanation:

• let numbers be x, y and z

{ \tt{z = 8y - 9 -  -  - (eqn \: 1)}} \\  \\ { \tt{10x = 8y - 7 -  -  - (eqn \: 2)}} \\  \\ { \tt{x + y + z = 8 -  -  - (eqn \: 3)}}

• from eqn 2, make x the subject:

{ \tt{x =  \frac{8y - 7}{10} }} \\

• substitute all variables in eqn 3:

{ \tt{ \frac{8y - 7}{10}  + y + 8y - 9 = 8}} \\  \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\  \\ { \tt{98y = 177}} \\  \\ { \boxed{ \tt{ \: y = 1.8}}}

• find z

{ \tt{z = 8y - 9}} \\  \\ { \tt{z = 8(1.8) - 9}} \\  \\ { \tt{z = 14.4 - 9}} \\  \\ { \boxed{ \tt{ \: z = 5.4 \: }}}

• find x:

{ \tt{x =  \frac{8(1.8) - 7}{10} }} \\  \\ { \tt{x =  \frac{7.4}{10} }} \\  \\ { \boxed{ \tt{ \: x = 0.74 \: }}}

Rounding to nearest value:

{ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{  \rm{z = 5}}}

7 0
2 years ago
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