The bearings of ships A and B from a port P are 225° and 116° respectively. Ship A is 3.9km from ship B on a bearing of 258°.
1 answer:
Answer:
- 2.54 km
Step-by-step explanation:
<em>See the attached</em>
All given details are reflected in the diagram (not to scale)
- PA is at 225°, PB is at 116°, BA is at 258°
- AB = 3.9 km
- AP = x
- m∠P = 225° - 116° = 109°
- m∠A = 258° - 225° = 33°
- m∠B = 180° - (109° + 33°) = 38°
<u>Use the law of sines:</u>
- x/ sin 38° = 3.9 / sin 109°
- x = 3.9 sin 38° / sin 109°
- x = 2.54 km (rounded)
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