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malfutka [58]
4 years ago
10

Three students need to produce a prime factorization of 48. Donna states that the first factors in the tree should be 6 and 8. L

arry states that the first factors in the tree should be 4 and 12. Trish states that the initial factors of 48 do not affect the prime factorization. Explain why Trish is correct
Mathematics
2 answers:
VARVARA [1.3K]4 years ago
5 0

Sample Response: A prime factorization is the product of the prime numbers that multiply to give the original number. 48 will have a prime factorization of 2(2)(2)(2)(3), or 24(3), regardless of the initial factors.


Gennadij [26K]4 years ago
4 0
If we start with 6 and 8, we can break 6 up into 2*3 and 8 into 2*2*2, thus getting a prime factorization of 2*2*2*2*3, or 2^4 *3.

If we begin with 4 and 12, 4 breaks into 2*2 and 12 into 2*2*3, so the prime factorization of 48 is still 2^4 *3.

The starting factors do not matter, since the answer comes out to be the same. There is exactly one correct answer- it doesn't matter how it's found.

Hope this helps! :)
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<u><em>Step(i):-</em></u>

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<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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