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mr Goodwill [35]
2 years ago
12

Determine the slopes of the following equation using their intercepts​

Mathematics
1 answer:
Olin [163]2 years ago
8 0

Answer:

yo slide me that number ong

Step-by-step explanation:

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Use the coordinates J(7, 8), K(1, 2) and L(5, 2) for AJKL.
Lerok [7]

Answer:

4.3

Step-by-step explanation:

6 0
2 years ago
The elves at Santa’s Workshop are trying to wrap the biggest box they can with the last bit of wrapping paper they have. All of
valina [46]

Answer:

The length of the box is 2×√30 inches long, the width of the box is 2×√(10/3) inches long, while the height of the box is √30 inches long

Step-by-step explanation:

The given parameters are;

The length of the last rectangular prism box = 3 × The width of the box

The area of the available wrapping paper = 240 in.²

Let L represent the length of the rectangular prism box, let W represent the width of the rectangular prism box and let h, represent the height of the rectangular box

Therefore, we have;

L = 3 × W

The surface area of the box, A = 2 × L × W + 2 × L × h + 2 × W × h

Whereby, L = 3 × W, we have;

A = 2 × 3 × W × W + 2 × 3 × W × h + 2 × W × h = 8·h·W + 6·W²

A = 8·h·W + 6·W² = 240

8·h·W + 6·W² = 240

8·h·W = 240 - 6·W²

h = (240 - 6·W²)/(8·W)

The volume,  V = L × W × h

∴ V = 3 × W × W × h = 3 × W² × h

V = 3 × W² × h

∴ V = 3 × W² × (240 - 6·W²)/(8·W) = 3/8 × W × (240 - 6·W²) = 90·W - 9/4·W³

dV/dW = d(90·W - 9/4·W³)/dW = 90 - 27/4·W²

At the maximum point, dV/dW = 0, which gives;

dV/dW = 90 - 27/4·W² = 0 at maximum point

27/4·W² = 90

W² = 4/27 × 90 = 40/3

W = ±√(40/3) = ±2×√(10/3)

Differentiating again and substituting gives;

d²V/dW² = d(90 - 27/4·W²)/dW =  - 27/4·W

Given that when W = 2×√(10/3), d²V/dW² is negative, and when W = -2×√(10/3), d²V/dW² is positive, W = 2×√(10/3) is the local maximum point

Therefor, the dimensions of the box are;

W = 2×√(10/3)

L = 3 × W = 3 × 2×√(10/3)

L = 3 × 2×√(10/3) = 2×√30

L = 2×√30

L = 6 ×√(10/3)

h = (240 - 6·(2×√(10/3))²)/(8·(2×√(10/3))) = √30

h = √30

Therefore, the length of the box is 2×√30 inches long, the width of the box is 2×√(10/3) inches long, while the height of the box is √30 inches long.

6 0
2 years ago
Some help me again lol please no links please
Alexus [3.1K]
It’s B hope this helps
5 0
3 years ago
The system of equations is graphed on the coordinate plane.
cricket20 [7]

It would be: (x,y) = (-1,-1)

-x-2 = 3x+2

3x+x = -2-2

x = -4/4

x = -1

Put that value in 1st equation, y =  -(-1)-2 = 1-2 = -1 SOLVED


6 0
3 years ago
Read 2 more answers
Help as soon possible thank you ​
Sergeeva-Olga [200]

<u>Answer:</u>

The correct answer option is D. (-2, 1).

<u>Step-by-step explanation:</u>

We are given the coordinates of the square A"B"C"D" after the rule is applied and we are to find the coordinates of the vertex A.

For that, we will reverse the rule.

A" = (-5, -3)

x: - 5 + 4 = -1

y: - 3 + 1 = -2

Now we will reverse the 90 degrees counter in counter clockwise rotation:

(x, y) ---> (y, -x)

(-1. -2) ---> (-2, -(-1)) = (-2, 1)

8 0
3 years ago
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