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yanalaym [24]
3 years ago
13

The radius of a circle is 3.9 in. Find the circumference to the nearest tenth.

Mathematics
2 answers:
masha68 [24]3 years ago
8 0

Answer:

C = 24.5 in

Step-by-step explanation:

Formula to find the circumference of a circle is :

C = 2πr

Here,

r ⇒ radius

So let us solve now.

C = 2πr

C = 2 × π × r

C = 2 × 3.14 × 3.9

C = 24.492 in

So, they've asked for nearest 10th.

Therefore, the answer will be 24.5 in.

Hope this helps you :-)

Let me know if you have any other questions :-)

KIM [24]3 years ago
5 0

Answer:

\huge{ \boxed{\boxed{\tt Circumference≈24.5 \: in.}}}

Step-by-step explanation:

<u>Given:-</u>

Radius of the circle = 3.9 in.

<u>To Find:-</u>

The Circumference

<u>Solution:-</u>

We know that the formula of Circumference is :

\boxed{ \sf \: Circumference = 2\pi{r}}

Note that r equals to <em>radius</em> which is given.

<u>Now,Put the value of radius (r) :-</u>

\sf \implies \: Circumference = (2\pi \times 3.9) \; in.\:

We know that the value of π is :-

\boxed{\sf  \: \pi = 3.14}

<u>So put the value of π :-</u>

\sf \implies{Circumference} =( 2 \times 3.14 \times 3.9 )in.

Simplify this:

<u>Multiply 2 and 3.14 :-</u>

\sf \implies{Circumference} = (6.28 \times 3.9) \: in.

<u>Multiply 6.28 and 3.9 :-</u>

\sf \implies{Circumference} = 24.492\; in.

Hence,the circumference of the circle would be 24.492 in. .

But We are asked to find the circumference to the nearest Tenth.

So,<u>th</u><u>e</u><u> </u><u>Nearest Tenth of 24.492</u><u> </u><u>in.</u><u> is :-</u>

\sf \implies{Circumference} ≈ 24.5 \: in.

Hence, the circumference to the nearest Tenth of the circle would be;

\boxed{\sf {Circumference} ≈ 24.5\;  in.}

We're done!

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

:)

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Answer:

The answer to your question is 43.8 mL of acid.

Step-by-step explanation:

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What is the measure of angle 1?
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Answer:

27 degrees

Step-by-step explanation:

The easy way is by remembering the formula (a-b)/2=c, where a is the larger angle, and b is the smallest angle. (90-36)/2=27.

The longer, more drawn out answer goes as follows. See the image to understand the notation I use:

  1. AOE + BOD + BOA + DOE = 360
  2. AOE + BOD = 90 + 36 = 126
  3. BOA + DOE = 360 - AOE - BOD = 234
  4. Since the sum of a triangle's angles is 180, ODE = (180 - DOE) / 2
  5. Likewise, OBA = (180 - BOA) / 2
  6. Since CDE is 180, CDO = 180 - ODE = 180 - (180 - DOE) / 2
  7. Likewise, CBA is 180, so CBO = 180 - OBA = 180 - (180 - BOA) / 2
  8. The interior angles of the irregular polygon CBOD add up to 360, so CBO + CDO + BOD + BCD = 360.
  9. Substituting what we already found, 180 - (180 - BOA)/2 + 180 - (180 - DOE)/2 + 36 + BCD = 360
  10. Cleaning it all up, we get 180 + (BOA + DOE)/2 + 36 + BCD = 360
  11. As we found in line 3, BOA + DOE = 234, so substituting that in, 180 + 117 + 36 + BCD = 360
  12. Finally, solving for BCD (360 - 36 - 117 - 180) we get our answer, 27

Note: The long drawn out method shown above is a way to derive the formula for the secant theorem. You do not need to use this method every time. Just remember, large angle minus small angle, all divided by 2. That is it.

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