Answer:
The y-coordinate of their intersection point is 3
That is y=3
Step-by-step explanation:
Given two lines are y=6x+15 and y=mx+4
Given that the two lines intersect at x=-2
To find the y coordinate of their intersection point :
Equating the two lines
6x+15=mx+4
6x+15-mx-4=0
6x-mx+11=0
(6-m)x+11=0
At x=-2 (6-m)x+11=0
(6-m)(-2)+11=0
(6-m)(-2)=-11
Substitute the value in y=mx+4 we get
At x=-2 
Therefore y=3
Therefore the y-coordinate of their intersection point is 3
Answer:
144.9 <= x <= 145.5
Step-by-step explanation:
145.2 + 3 = 145.5
145.2 - 3 = 144.9
144.9 <= x <= 145.5
The length of the arc =R × theta
theta =the length of the arc /R
theta =16/19.36
that's what i know
Well, we can be sure that whatever the width is, we can call it ' W '. Then, from information in the question, the length of the garden is ' 3W '.
Now, the perimeter of a rectangle is (length + width + length + width). Using the fancy algebra labels I just gave them, that's (3W + W + 3W + W). And now I can go through that, add up all the Ws, and get a total of 8W for the perimeter.
But he question tells us that the perimeter is 24 yards, so 8W = 24 yds.
Divide each side of that equation by 8, and we discover that W = 3 yds. And if THAT's true, then 3W = 9 yds. Bada bing ! We have the dimensions of the garden.
It's 3 yards wide and 9 yards long.
