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2 years ago

In △ABC, the altitudes from vertices B and C intersect at point M, so that BM = CM. Prove that △ABC is isosceles.

Mathematics

1 answer:

AlekseyPX2 years ago

3 0

Answer:

m∠MBC=m∠MCB by reason base angle theorem

Step-by-step explanation:

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During a cold front, the temperature in Denver, Colorado, dropped from 7 degrees C to -5 degrees C. What was the change in the t

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3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

Can someone please answer this question I need it today please show work and please answer it correctly i

svlad2 [7]

Answer:

24) $495

25) 14%

26) 25/X = 83/100

27) 0.7p

28) x + .085x and 1.085x

29) $221.90

30) $24.10

31) $6.13

32) 40%

Step-by-step explanation:

24) 600 - (600 × 0.25) = 450

450 × 1.10 = 495

25) (106 - 93) ÷ 93 = 0.13978

0.13978 × 100 = 13.978 ~ 14

27) 1.0 - 0.3 = 0.7

28) 1.00 + 0.085 = 1.085

29) 100% - 15% = 85%

240 × 0.85 = 204

204 × 1.0875 = 221.85

30) 25.89 × 4 = 103.56

103.56 + 179.99 = 283.55

283.55 × 0.085 = 24.10175

31) 8.75 × 0.70 = 6.125

32) 80 - (80 × 0.40) = 48

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3 years ago

Add. [12 −6 −10]+[−2 14 5 15]

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Answer:

Step-by-step explanation:

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