Triangle ABC is dilated by a scale factor of 1.5 to create triangle A'B'C'. Which of

Mathematics

1 answer:

yKpoI14uk [10]1 year ago

7 0

Answer:

C. Segment AB is congruent to segment A'B'.

Step-by-step explanation:

Since ABC is being dilated by 1.5, it means that A'B'C will be bigger than ABC.

So, since A'B'C will be bigger than ABC, it sides will also be bigger than the sides in ABC.

And since the sides/segments are bigger than the original, they are not congruent (congruent means equal).

You might be interested in

Calculus: Help ASAP

Serggg [28]

$\bf \displaystyle \int\limits_{-1}^{0}~(4x^6+2x)^3(12x^5+1)\cdot dx\\\\
-------------------------------\\\\
u=4x^6+2x\implies \cfrac{du}{dx}=24x^5+2\implies \cfrac{du}{2(12x^5+1)}=dx\\\\
-------------------------------\\\\
\displaystyle \int\limits_{-1}^{0}~u^3\underline{(12x^5+1)}\cdot\cfrac{du}{2\underline{(12x^5+1)}}\implies \cfrac{1}{2}\int\limits_{-1}^{0}~u^3\cdot du\\\\
-------------------------------\\\\$

$\bf \textit{now, we'll change the bounds, using u(x)}
\\\\\\
u(-1)=4(-1)^6+2(-1)\implies u(-1)=2
\\\\\\
u(0)=4(0)^6+2()\implies u(0)=0\\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{2}^{0}~u^3\cdot du\implies \left. \cfrac{1}{2}\cdot \cfrac{u^4}{4} \right]_{2}^{0}\implies \left. \cfrac{u^4}{8} \right]_{2}^{0}\implies [0]-[2]\implies -2$

5 0

2 years ago

F(x) = -x - 3 Find f(-4) f(-4) = -(-4) -3

skelet666 [1.2K]

Answer:

$\boxed{ \bold{ \boxed{ \sf{f( - 4) = 1}}}}$