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3 years ago

32 is closer to_ than it is to_.

Mathematics

2 answers:

IgorC [24]3 years ago

3 0

32 is closer to 33 than it is to 40

Lostsunrise [7]3 years ago

3 0

To 33 than to 40..............

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An equilateral ∆ has sides of length 16 cm. Find the length of an altitude.

inn [45]

The length of the altitude is $8\sqrt{3}$

Explanation:

Let ABC be an equilateral triangle.

It has sides of length 16 cm

Let AD be the altitude of the triangle.

We need to determine the length of an altitude.

Let AC = 16 cm and CD = 8 cm

Let us consider the right angled triangle ADC

Using the Pythagorean theorem, we have,

$AC^2=AD^2+DC^2$

Substituting the values, we get,

$16^2=AD^2+8^2$

$256=AD^2+64$

$192=AD^2$

$8\sqrt{3}=AD$

The length of the altitude is $8\sqrt{3}$

5 0

3 years ago

-3(x+2)=12. solve for x

bagirrra123 [75]

Steps to solve:

-3(x + 2) = 12

~Distributive Property

(-3 * x) + (-3 * 2) = 12

~Simplify

-3x - 6 = 12

~Add 6 to both sides

-3x - 6 + 6 = 12 + 6

~Simplify

-3x = 18

~Divide -3 to both sides

-3x/-3 = 18/-3

~Simplify

x = -6

Best of Luck!

8 0

3 years ago

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Liam and his children went into a restaurant and where they sell drinks for $2 each and tacos for $3.50 each. Liam has $30 to sp

scoray [572]

Answer: the maximum number of drinks Liam can buy is 4 without over exceeding his price limit.

work:
$3.50 for 5 tacos is $17.50
9 - 5 tacos = 4 drinks
4 drinks x $2 = $8
$17.50 + $8 = $25.50 out of $30 price limit

3 0

2 years ago

Read 2 more answers

What's the difference between perpendicular bisectors and altitudes

FromTheMoon [43]

Perpendicular bisectors help you find the centroid; altitudes help find the orthocenter. This is all in a triangle.

4 0

3 years ago

4/28 - [10 + (3 + 1) x 2]]

Sholpan [36]

Answer:

$\frac{4}{28}-\left(10+\left(3+1\right)x\cdot \:2\right)=-8x-\frac{69}{7}$

8 0

3 years ago