All categories

3 years ago

How do solve 3/8j = 6

1 answer:

6 0

If you would like to solve 3/(8j) = 6 for j, you can do this using the following steps:

3/(8j) = 6
3 = 6 * 8j
3 = 48j
j = 3/48
j = 1/16

If you would like to solve (3/8) * j = 6 for j, you can do this using the following steps:

(3/8) * j = 6
j = 6 * 8/3
j = 16

You might be interested in

Line segment EF is shown on a coordinate grid:

VikaD [51]

The answer would be A.

It is reflected across the x-axis means that point E' will be at (-3, -2) and point F' would be at (-1,-2)

the length of the line would be the same regardless of anyway you translate, rotate, or reflect it. Only if you dilate it, then an object's size can change.

Hope that helps :)

5 0

3 years ago

Read 2 more answers

65% of 150 estimate percent

Ksju [112]

Answer:

97.5

Brainliest answer pls

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Maggie only wore sandals tracker on two of the days that she trained so from her fitness trackers she verified that on the third

KIM [24]

We know form our problem that the third day she biked 20 miles, so we have the point (3,20). We also know that on the eighth day she biked 35 miles, so our second point is (8,35).

To relate our two point we are going to use the slope formula: $m= \frac{x_{2}-x_{1}}{y_{2}-y_{1}}$
We can infer form our points that $x_{1}=3$ , $y_{1}=20$ , $x_{2}=8$ , and $y_{2}=35$ . so lets replace those values in our slope formula:
$m= \frac{35-20}{8-3}$
$m= \frac{15}{5}$
$m=3$

Now that we have the slope, we can use the point-slope formula determine the equation of the line that best fit the set for Maggie’s data.
Point-slope formula: $y-y_{1}=m(x-x_{1})$
$y-20=3(x-3)$
$y-20=3x-9$
$y=3x+11$

We can conclude that the equation of the line that best fit the set for Maggie’s data is $y=3x+11$ .

3 0

4 years ago

Find all the values of x where the tangent line is horizontal. 2x^3+36x^2+192x+12

Afina-wow [57]

At x = -4 and -8
Take the derivative of the given equation to find rate of change of the graph.
f'(x) = 6x^2 + 72x + 192
At a horizontal tangent, f'(x) = 0, so set the equation equal to 0 and solve. Eventually you get x = -4 and -8

3 0

3 years ago

Help please! Thank you!!

umka2103 [35]

Answer:

i dont know what it is

Step-by-step explanation:

maybe a

3 0

3 years ago