All categories

3 years ago

HELP PLEASE 50 PT

Mathematics

2 answers:

nikdorinn [45]3 years ago

8 0

Answer:

102 cups

Step-by-step explanation:

314-212=102

Brut [27]3 years ago

4 0

102 cups of sugar.

Hope this helps

You might be interested in

Help pleaseee guysss

Anvisha [2.4K]

Answer:

Step-by-step explanation:

f(x)=2x^2

f(x)=y

y=2x^2

y=2(-2)^2

y=2(4)

y=8

y=2x^2

y=2(-1)^2

Y=2

Y=2X^2

y=2(0)^2

y=0

y=2x^2

y=2(1)^2

y=2

y=2x^2

y=2(2)^2

y=8

DON'T FORGET BODMAS

6 0

3 years ago

Find the area of the shaded region.

Citrus2011 [14]

Answer:

pi × 18cm^2

Or approximately,

56.52cm^2 (using 3.14 for pi)

56.5487cm^2 (using pi button on calculator)

Step-by-step explanation:

Area of a circle is pi times [radius squared].

All circles are 360°.

Problem can be solved by finding area of whole circle, and then using ratios.

Whole Circle: area = pi × (9cm)^2 = pi × 81cm^2

80° / 360° = Area[shaded] / (pi × 81cm^2)

pi × 18cm^2 = Area[shaded]

((If you read my answer before the edit, I am sorry. I made a calculator error.))

3 0

3 years ago

Which polynomial function has a leading coefficient of 1 and roots 21 and 31 with multiplicity 1?

schepotkina [342]

Answer:

Which i think is the first one, there may just be a typing error.

Step-by-step explanation:

A polynomial of order n has the following format:

$f(x) = a(x - x_{0})(x - x_{1})...(x - x_{n-1})$

In which a is the leading coefficient, $x_{0}, x_{1},..., x_{n-1}$ are the roots.

If a root appears m times, they are said to have multiplicity m.

Leading coefficient of 1 and roots 21 and 31 with multiplicity 1

$f(x) = 1(x - 21)(x - 31)$

So the correct answer is:

$f(x) = 1(x - 21)(x - 31)$

Which i think is the first one, there may just be a typing error.

8 0

3 years ago

What is the value of z in the equation 2z + 6 = −4? 5 1 −1 −5

daser333 [38]

1. Subtract 6 from both sides now you would get..

2z=-10

Now divide each side by 2z and you get

z= -5

So the answer is -5

5 0

3 years ago

Read 2 more answers

If the slope of a line is -1 and two points on the line are (-9, 3) and (-10, r), what is the value of r?

ANEK [815]

Answer:

$r=4$

Step-by-step explanation:

We know that the slope of the line is -1.

We also know that the line passes through (-9, 3) and (-10, r).

We want to find the value of r.

First, let's figure out the equation of our line. We can use the point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope and (x₁, y₁) is a point.

So, let's substitute -1 for m. Since we know the point (-9, 3), let's use this for (x₁, y₁).

Substitute:

$y-(3)=-1(x-(-9))$

Simplify:

$y-3=-(x+9)$

Distribute:

$y-3=-x-9$

Add 3 to both sides. So, our equation is:

$y=-x-6$

It passes through (-10, r) and we want to find the value of r. So, let's substitute -10 for x and r for y, since -10 is our x and r is our y. So:

$r=-(-10)-6$

Evaluate for r. Distribute:

$r=10-6$

Subtract:

$r=4$

So, the value of r is 4.

And we're done!

6 0

3 years ago