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Andrews [41]
3 years ago
11

The sum of 8 times a number and 15 is 7

Mathematics
1 answer:
Bumek [7]3 years ago
5 0
8x+15=7

answer: x= 1 hope this help
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Can anyone help? Im giving 100 points for it its all i have
olga_2 [115]

Answer: i tried

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Step-by-step explanation:

3 0
3 years ago
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The table shows the possible outcomes of spinning the given
olganol [36]

Spinning the spinner and tossing the coin is an illustration of probability

The probability of spinning a 1 and tossing a head is 0.10

<h3>How to determine the probability?</h3>

From the table, we have the following parameters:

Total outcomes, n = 10

A 1 and a head, n(H1) = 1

So, the probability of spinning a 1 and tossing a head is:

P(H1) = n(H1)/n

Substitute known values

P(H1) = 1/10

Evaluate the quotient

P(H1) = 0.10

Hence, the probability of spinning a 1 and tossing a head is 0.10

Read more about probability at:

brainly.com/question/251701

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2 years ago
Write an equation for each graph in a slope<br> Intercept form
Mazyrski [523]

Answer:

Write the equation of the graph in slope intercept form

To write a slope-intercept equation from a graph, find the point where the graph crosses the y-axis, b, and the slope, m, and plug them into the equation y=mx+b.

Step-by-step explanation:

hope this helps

6 0
3 years ago
Mendel crossed peas having round seeds and yellow cotyledons (seed leaves) with peas having wrinkled seeds and green cotyledons.
maw [93]

Answer:

1/16

Step-by-step explanation:

This question involves two distinct genes; one coding for seed shape and the other for cotyledon color. The alleles for round seeds (R) and yellow cotyledons (Y) are dominant over the alleles for wrinkled seed (r) and green cotyledon (y) respectively.

In a cross between a truebreeding (i.e. same alleles for both genes) pea having round seeds and yellow cotyledon (RRYY) and a truebreeding pea having wrinkled seeds and green cotyledon (rryy), the F1 offsprings will all possess a heterozygous round seed and yellow cotyledon (RrYy).

The F1 offsprings (RrYy) will produce the following gametes: RY, Ry, rY, and ry. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a ratio 9:3:3:1.

According to the question, 3/16 of the F2 offsprings will possess round seeds and green cotyledons, however, only 1 of them will be truebreeding i.e. RRyy. Hence, 1/16 of the F2 offsprings will be truebreeding for round seeds and green cotyledons.

3 0
3 years ago
Mr. Gupta gave his students a quiz with three questions on it. Let X represent the number of questions
irakobra [83]

Answer:

24.5 points

8 points

Step-by-step explanation:

khan academy

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