Answer: i tried
1. 7,350.98
2. 432
3. 2016
4. 311404
Step-by-step explanation:
Spinning the spinner and tossing the coin is an illustration of probability
The probability of spinning a 1 and tossing a head is 0.10
<h3>How to determine the probability?</h3>
From the table, we have the following parameters:
Total outcomes, n = 10
A 1 and a head, n(H1) = 1
So, the probability of spinning a 1 and tossing a head is:
P(H1) = n(H1)/n
Substitute known values
P(H1) = 1/10
Evaluate the quotient
P(H1) = 0.10
Hence, the probability of spinning a 1 and tossing a head is 0.10
Read more about probability at:
brainly.com/question/251701
Answer:
Write the equation of the graph in slope intercept form
To write a slope-intercept equation from a graph, find the point where the graph crosses the y-axis, b, and the slope, m, and plug them into the equation y=mx+b.
Step-by-step explanation:
hope this helps
Answer:
1/16
Step-by-step explanation:
This question involves two distinct genes; one coding for seed shape and the other for cotyledon color. The alleles for round seeds (R) and yellow cotyledons (Y) are dominant over the alleles for wrinkled seed (r) and green cotyledon (y) respectively.
In a cross between a truebreeding (i.e. same alleles for both genes) pea having round seeds and yellow cotyledon (RRYY) and a truebreeding pea having wrinkled seeds and green cotyledon (rryy), the F1 offsprings will all possess a heterozygous round seed and yellow cotyledon (RrYy).
The F1 offsprings (RrYy) will produce the following gametes: RY, Ry, rY, and ry. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a ratio 9:3:3:1.
According to the question, 3/16 of the F2 offsprings will possess round seeds and green cotyledons, however, only 1 of them will be truebreeding i.e. RRyy. Hence, 1/16 of the F2 offsprings will be truebreeding for round seeds and green cotyledons.
Answer:
24.5 points
8 points
Step-by-step explanation:
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