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tino4ka555 [31]
2 years ago
12

Expo Models Help me with this questions please

Mathematics
1 answer:
Aneli [31]2 years ago
6 0
This is the write answer to Exporiental decay
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Given AB intersects DE at point C. prove: DCB = ECA. What is the missing reason in step 5
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Answer: the answer is linear pair

Step-by-step explanation:

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3 years ago
I am needing help with this question!!
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The answer is C. y = - 2x - 1

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To check the correctness of the answer to a multiplication example, divide the
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Multiplicand is the number that gets multiplied, multiplier is the number that you are multiplying by, product is the result of mulptiplication multiplicand by multiplier.


Let a be a multiplicand, b be a multiplier and c be a product, then


a·b=c.


To check the correctness of the answer to a multiplication example, you should divide the product c by the multiplier b:


c÷b=a.


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2 years ago
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A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
2 years ago
Math is often used to
Sholpan [36]
Answer: A I think
Seems like the correct one
8 0
3 years ago
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