One side of a triangle is 4 cm shorter than the base, x. The other side is 3 cm longer than the base. What lengths of the base w ill allow the perimeter of the triangle to be at least 29 cm? Write your answer as an Inequality.
1 answer:
So the base is X cm, one side is X+4 cm and the last side is X+3 cm. We know that all those sides combined need to be at least 29cm. This gives us 3X + 7 > 29cm. If we solve this, we get 3X > 22cm which means X > 22/3 which means X is bigger than 7 1/3 cm
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what did u get?
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You can use (a+b)2 = a2+2ab+b2.
(2x - 3)2 = (2x)2 + 2(2x)(-3) + (-3)2 = 4x2 - 12x + 9
Or you can use FOIL.
(2x - 3)2 = (2x - 3)(2x - 3) = (2x)2 + (2x)(-3) + (-3)(2x) + (-3)2 = 4x2 - 12x + 9
hope I could be helpful