Ab=81, a=81/b
s=a+b using a from above in this we get:
s(b)=81/b +b
s(b)=(81+b^2)/b
ds/db=(2b*b-81-b^2)/b^2
ds/db=(2b^2-81-b^2)/b^2
ds/db=(b^2-81)/b^2
d2s/db2=(2b^3-2b^3+81)/b^4
d2s/db2=81/b^4 since b is positive we know that the acceleration is positive so that when ds/db=0 it is a minimum for s(b)
ds/db=0 only when b^2-81=0, b^2=81, b=9
The two positive numbers are 9 and 9.
Answer:
Solid Sphere
Step-by-step explanation:
According to the question, the three shapes have equal masses (m), radii (R) (and diameter).
The shape with the least mass moment of inertia will have the highest acceleration
Let IC represents Inertia
According to calculations, the inertia of
Solid Sphere: IC=(2/5)mR²
Solid Cylinder: IC=½mR²
Hollow Pipe: IC=⅔mR²
Where m = mass of the shape
And R is the Radius of the shape
By comparison, the solid sphere has the least mass of inertia and hollow Pipe has the most mass of inertia.
So, solid sphere will get to the bottom first.
Your answer is y = 1/2x + 5
Answer:
The sum of the first 47 terms of the given series = 6016
Step-by-step explanation:
Given the sequence
13, 18, 23, ...
An arithmetic sequence has a constant difference 'd' and is defined by


As the difference between all the adjacent terms is the same.
so


Arithmetic sequence sum formula

Put the values








Thus, the sum of the first 47 terms of the given series = 6016
I hope this helps you
1/3.3.3 divided 3s
3