What is the answer to 72% of 14?

Five workers dig a trench 5 yards long in 5 hours. How many workers are needed to dig a 100 yards long in 100 hours?

Pavlova-9 [17]

I think it would require 100 workers since 1 worker digs up 1 yard.

Hope this helps.

7 0

2 years ago

A softball team won 95% of 120 games. How many games did they win

dmitriy555 [2]

Answer:

114 games

Step-by-step explanation:

0.95 x 120=114

they won 114 games

5 0

3 years ago

Read 2 more answers

Px+35=-6x+Q

julia-pushkina [17]

The answer to this question is C

6 0

2 years ago

Directions - Identify the key components, create an exponential equation, then answer the questions.

Tamiku [17]

Answer:

Directions - Identify the key components, create an exponential equation, then answer the questions.

Exponential Form: y=a\cdot b^{x},\ a\ is\ the\ \textit{starting}\ \textit{value},\ b\ is\ the\ base\ (rate).\y=a⋅b

x

, a is the starting value, b is the base (rate).

In a small town, the stray dog population is rapidly increasing. there are currently 15 stray dogs, and it is estimated that the population will triple every year. How many dogs will there be after 1 year? 2 years? 3 years?

1) a = 15

4) Dogs after 1 years = 45

2) b = 3

5) Dogs after 2 years = 135

3) Equation:

y= 15 ×3x

6) Dogs after 3 years =

405

Step-by-step explanation:

8 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

So

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

2 years ago