Ask question

Ask question

All categories

4 years ago

7

Determine the molar concentration of ammonium ions, NH4 , in a solution that results when 4.53 g of (NH4)2SO4 are dissolved in 1

00 mL of water.

1 answer:

sertanlavr [38]4 years ago

4 0

Answer:

Molar concentration of solution is 0.343 M

Explanation:

Molar mass of $(NH_{4})_{2}SO_{4}$ is 132.14 g/mol

So, 4.53 g of $(NH_{4})_{2}SO_{4}$ = $\frac{4.53}{132.14}mol$ of $(NH_{4})_{2}SO_{4}$ = 0.0343 mol of $(NH_{4})_{2}SO_{4}$

Molar concentration means how many moles of solute are present in 1000 mL of solution

Here solute is $(NH_{4})_{2}SO_{4}$

Let's assume total volume of solution is equal to volume of water as solids have negligible volume with respect to liquid

So, molar concentration of solution = $\frac{0.0343\times 1000}{100}M=0.343M$

You might be interested in

A piece of glass has a temperature of 83˚C. Liquid that has a temperature of 43˚C is poured over the glass, completely covering

Lerok [7]

Answer: The specific heat of the liquid is $2520J/kg^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

.................(1)

where,

q = heat absorbed or released

= mass of glass = x kg

= mass of liquid = x kg

= final temperature =

$T_1$ = temperature of glass = $83^oC$

$T_2$ = temperature of liquid = $43^oC$

$c_1$ = specific heat of glass = $840J/kg^0C$

$c_2$ = specific heat of liquid= ?

Now put all the given values in equation (1), we get

$-[(x\times 840\times (53-83)]=x\times c_2\times (53-43)$

$c_2=2520J/kg^0C$

Therefore, the specific heat of the liquid is $2520J/kg^0C$

5 0

3 years ago

Please answer this if you do I will answer your questions!!

monitta

Answer:

i think the forces are the same and size and in opposite directions

Explanation:

4 0

3 years ago

Read 2 more answers

Acenapthalene has the empirical formula C6H5. A solution of 0.515 g of acenapthalene in 15.0 g CHCl3 boils at 62.5oC. The normal

german

Answer:

The molecular formula of an ascenapthalene is $C_{12}H_{10}$

Explanation:

$\Delta T_b=K_b\times m$

$\Delta T_b=K_b\times \frac{\text{Mass of acenapthalene}}{\text{Molar mass of acenapthalene}\times \text{Mass of chloroform in Kg}}$

where,

$\Delta T_f$ =Elevation in boiling point = $(62.5-61.7)^oC=0.8^oC$

Mass of acenapthalene = 0.515 g

Mass of $CHCl_3$ = 15.0 g = 0.015 kg (1 kg = 1000 g)

$K_b$ = boiling point constant = 3.63 °C/m

m = molality

Now put all the given values in this formula, we get

$0.8^0C=3.67 ^oC/m\times \frac{0.515}{\text{Molar mass of acenapthalene}\times 0.015kg}$

$\text{Molar mass of acenapthalene}=155.7875 g/mol$

Let the molecule formula of the Acenapthalene be $C_{6n]H_{5n}$

$6n\times 12 g/mol+5n\times 1 g/mol=155.7875 g/mol$

n = 2.0

The molecular formula of an ascenapthalene is $C_{12}H_{10}$

4 0

4 years ago

What is the elements

Margaret [11]

DescriptionIn chemistry an element is a species of atom having the same number of protons in its atomic nuclei. For example, the atomic number of oxygen is 8, so the element oxygen describes all atoms which have 8 protons. In total, 118 elements have been identified.

4 0

3 years ago

Read 2 more answers

Based on your knowledge of intermolecular forces and trends, select the statement that is most accurately compares HF and HCl.

tangare [24]

Answer:

(A) The intermolecular attraction between HF molecules are stronger than between HCl molecules mainly to due hydrogen bonding.

Explanation:

Since Flourine is highly electronegative and as such, when it bonds with Hydrogen it forms a hydrogen bond. Whereas the HCL molecule is a polar molecule whose inter-molecular forces are dipole dipole interactions. Although a Hydrogen bond is a type of dipole dipole interaction it is stronger than the traditional dipole dipole forces and London dispersion forces. HF also has a shorter bond length which makes the bond and inter-molecular forces stronger as compared to HCL.

8 0

3 years ago