Question

Determine the molar concentration of ammonium ions, NH4 , in a solution that results when 4.53 g of (NH4)2SO4 are dissolved in 100 mL of water.

Answer 1

Answer:

Molar concentration of solution is 0.343 M

Explanation:

Molar mass of $(NH_{4})_{2}SO_{4}$ is 132.14 g/mol

So, 4.53 g of $(NH_{4})_{2}SO_{4}$ = $\frac{4.53}{132.14}mol$ of $(NH_{4})_{2}SO_{4}$ = 0.0343 mol of $(NH_{4})_{2}SO_{4}$

Molar concentration means how many moles of solute are present in 1000 mL of solution

Here solute is $(NH_{4})_{2}SO_{4}$

Let's assume total volume of solution is equal to volume of water as solids have negligible volume with respect to liquid

So, molar concentration of solution = $\frac{0.0343\times 1000}{100}M=0.343M$