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aleksandrvk [35]
3 years ago
8

What is the ΔG for the following reaction at 25°C?

Chemistry
2 answers:
Pepsi [2]3 years ago
5 0
<span> The ΔG for the following reaction at 25°C of </span><span>N2O4(g) → 2NO2(g) is 5.32 kJ per mole.

2 (51.8) - 98.28 = 5.32 kJ per mole.

This is because t</span>he rate of the dissociation of N2O4 is equal to the rate of formation of N2O4.
ikadub [295]3 years ago
4 0
\Delta G_{global}=\Delta G_{products}-\Delta G_{reagents}\\\\&#10;\text{We should consider the stoichiometry:}\\\\&#10;\Delta G=2\Delta G_{NO_2}-\Delta G_{N_2O_4}\\\\&#10;\Delta G=2\cdot51.8-98.28=103.6-98.28\\\\&#10;\boxed{\Delta G=5.32~kJ}
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Which of the following processes absorbs energy? A) condensation of water on a wind shield of a car B) formation of copperC) bal
Alecsey [184]

Answer:

C) ball rollinflown a hill

Explanation:

The question asks to  identify the endothermic process in the list of options. By way of elimination, we have;

A) condensation of water on a wind shield of a car

Condensation is an exothermic process. That is, heat is given out as the gases change into the liquid state of matter.

B) formation of copper

This is an exothermic process. Capture of electrons by a cation is always exothermic.

C) ball rollinflown a hill

This is the correct option. Energy is absorbed by the ball as it moves on the hill

D) formation of ice from liquid water

Freezing is an example of exothermic reaction. Heat is given off to the surroundings.

E) oxide from copper and oxygen

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4 0
3 years ago
What is the balanced equation for the reaction of a solution of sodium sulfate is mixed with strontium chloride?
natta225 [31]

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6 0
3 years ago
Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe
leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as <u>molarity</u>, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

c = \frac{n}{V}

n = moles (unit mol)

V = volume (unit L)

<u>Find the molar mass (M) of potassium hydroxide.</u>

M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}

M_{KOH} = 56.106 \frac{g}{mol}

<u>Calculate the moles of potassium hydroxide.</u>

n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}

n_{KOH} = 0.25941(9)mol

Carry one insignificant figure (shown in brackets).

<u>Convert the volume of water to litres.</u>

V = \frac{500.0mL}{1}*\frac{1L}{1000mL}

V = 0.5000L

Here, carrying an insignificant figure doesn't change the value.

<u>Calculate the concentration.</u>

c = \frac{n}{V}

c = \frac{0.25941(9)mol}{0.5000 L}              

c = 0.5188(3) \frac{mol}{L}         <= Keep an insignificant figure for rounding

c = 0.5188 \frac{mol}{L}              <= Rounded up

c = 0.5188M               <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

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For the first one the answer is B. and the second one is D.
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