Question

A piece of glass has a temperature of 83˚C. Liquid that has a temperature of 43˚C is poured over the glass, completely covering it, and the temperature at equilibrium is 53˚C. The mass of liquid and glass is the same. If the specific heat of glass is 840 J/(kg˚C), determine the specific heat of the liquid.

Answer 1

Answer: The specific heat of the liquid is $2520J/kg^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,  

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

        .................(1)

where,

q = heat absorbed or released

= mass of glass = x kg

= mass of liquid = x kg

= final temperature =

$T_1$ = temperature of glass = $83^oC$

$T_2$ = temperature of liquid = $43^oC$

$c_1$ = specific heat of glass = $840J/kg^0C$

$c_2$ = specific heat of liquid= ?

Now put all the given values in equation (1), we get

$-[(x\times 840\times (53-83)]=x\times c_2\times (53-43)$

$c_2=2520J/kg^0C$

Therefore, the specific heat of the liquid is $2520J/kg^0C$